Applied Structural and Mechanical Vibrations Theory, Methods and Measuring Instrumentation 5 More SDOF—transient response and approximate methods 5 1 Introduction The harmonic excitation considered so.
Trang 1of the individual responses So, in principle, the complications seem to be more
of a mathematical nature rather than a physical nature, and such a statement
of the problem does not seem to add anything substantial to the understanding
of the behaviour of a linear SDOF system under the action of a complex excitingload However, things are not so simple; a number of different approaches andtechniques are available to deal with this problem and the choice is partly asubjective matter and partly dictated by the complexity of the situation, thefinal results that one wants to achieve and the mathematical tractability of thecalculations by means of analytical or computer-based methods
The first and main distinction can be made between:
• time-domain techniques
• frequency-domain techniques.
As the name itself implies, the first approach relies on the manipulation ofthe functions involved (generally the loading and the response functions) inthe domain of time as the independent variable of interest The important
concepts are ultimately the impulse response function and the convolution,
or Duhamel’s, integral.
On the other hand, the second technique is based on the powerful tool ofmathematical transforms: the manipulations are made in the domain of anappropriate independent variable (frequency, for example, hence the name)and then, if necessary, the result is transformed back to the domain of theoriginal variable
Trang 2The two approaches, as one might expect, are strictly connected and theresult does not depend on the particular technique adopted for the problem athand Unfortunately, except for simple cases, both techniques involve evaluations
of integrals that are not always easy to solve and their practical applicationmust often rely heavily on numerical methods which, in their turn, require therelevant functions to be ‘sampled’ at regular intervals of the independent variable.This ‘sampling’ procedure introduces further complications that belong to the
specific field of digital signal analysis, but they cannot be ignored when
measurements are taken and computations via electronic instrumentation areperformed Their basic aspects will be dealt in future chapters
Until a few decades ago the computations involved in frequency-domaintechniques were no less than those in a direct evaluation of the discreteconvolution in the time domain The development of a special algorithmcalled the fast Fourier transform [1] has completely changed this situation,cutting down computational time of orders of magnitude and makingfrequency techniques more effective
Both the convolution integral and the transform methods apply whenlinearity holds; for nonlinear systems recourse must be made to a directnumerical integration of the equations of motion, a technique which,obviously, applies to linear systems as well
When the predominant frequency of vibration is the most importantparameter and the system is relatively complex, the Rayleigh ‘energy method’and other techniques with a similar approach turn out to be useful to obtainsuch a parameter The simplest application represents a multiple- (or infinite-)degree-of-freedom system as a ‘generalized’ SDOF system after an educatedguess of the vibration pattern has been made The method is approximate (but
so are numerical methods, and in general are much more time consuming) andits accuracy depends on how well the estimated vibration pattern matches thetrue one Its utility lies in the fact that even a crude but reasonable guess oftenresults in a frequency estimate which is good enough for most practical purposes
5.2 Time domain—impulse response, step response and
convolution integral
Let us refer back to Fig 4.7 The SDOF system considered so far is a particularcase of the situation that this figure illustrates, i.e a single-input single-output
linear system where the output x(t) and the input f(t) (written as a force for
simplicity, but it need not necessarily be so) are related through a lineardifferential equation of the general form
(5.1)
Trang 3The coefficients a i and b j (i=1, 2, 3, ···, n; j=1, 2, 3, ···, r), that is the parameters
of the problem, may also be functions of time, but in general we shall consideronly cases when they are constants On physical grounds, this assumptionmeans that the system’s parameters (mass, stiffness and damping) do notchange, or change very slowly, during the time of occurrence of the vibrationphenomenon This is the case, for example, for our spring—mass-damperSDOF system whose equation of motion is eq (4.13), which is just a particularcase of eq (5.1)
Very common sources of excitation are transient phenomena and mechanical shocks, both of which are obviously nonperiodic and are
characterized by an energy release of short duration and sudden occurrence.Broadly speaking, we can define a mechanical shock as a transmission ofenergy to a system which takes place in a short time compared with thenatural period of oscillation of the system, while transient phenomena maylast for several periods of vibration of the system
An impulse disturbance, or shock loading, may be for example a ‘hammerblow’: a force of large magnitude which acts for a very short time.Mathematically, the Dirac delta function (Chapter 2) can be used to representsuch a disturbance as
(5.2)
where has the dimensions newton-seconds and describes an impulse (timeintegral of the force) of magnitude
(5.3)
One generally speaks of unit impulse when
From Newton’s second law fdt=mdv, assuming the system at rest before
the application of the impulse, the result on our system will be a suddenchange in velocity equal to without an appreciable change in itsdisplacement Physically, it is the same as applying to the free system the
initial conditions x(0)=0 and The response can thus be written(eq (4.8))
(5.4)for an undamped system, and (eq (4.27))
(5.5)
Trang 4for a damped system In both cases it is convenient to write the response as
(5.6)
where h(t) is called the unit impulse response (some authors also call it the
weighting function) and is given by
(5.7a)
for the undamped and damped case, respectively Equations (5.7a) represent
the response to an impulse applied at time t=0; if the impulse is applied at
(5.7b)
for and zero for since the change of variable from t to is
geometrically a simple translation of the coordinate axes to the right by anamount seconds In practice, an impact of duration ∆t of the order of
10–3 s (and ∆t is short compared to the system’s period) is acommon occurrence in vibration testing of structures In these cases, theconsiderations above apply
Figure 5.1 illustrates a graph of for a damped system with unitmass, damping ratio and damped natural frequency
Example 5.1 Let us consider the response of an undamped system to an
impulse of a constant force f0 that acts for the short (compared to the system’s
period) interval of time 0<t<t1 We assume the system to be initially at restand we have
(5.8)
Trang 5During the ‘forced vibration era’ (0<t<t1) the response of the system is given
by eq (4.63) where β=0 (because ω=0) and the particular integral is given
Trang 6(5.12)
and the approximations above hold for (or, better, ) By notingthat and that the impulse has a value from eq (5.11) weobtain in the limit
(5.13)
which is, as expected, the impulse response of the undamped system (eq(5.4)) It is left to the reader to determine how considerations similar to theones above lead to eq (5.5) for a damped system
A general transient loading such as the one shown in Fig 5.2 can beregarded as a superposition of impulses; each impulse is applied at time
and has a magnitude given by f( ) ∆ , with varying along the time axis
(shaded area in Fig 5.2)
Mathematically we can write
Trang 7The response to the impulse of eq (5.14) is
and the total response from time to time is obtained by summing
the effects of all the impulses up to the instant t, i.e.
(5.16)Passing to the limit of the summation becomes an integral and theresponse from to is finally given by
that its evaluation is performed through multiplication of f( ) by each
incremental shift in As the present time t varies the impulse response scans the excitation function, producing a weighted sum of past inputs
up to the present instant; so, in terms of the superposition principle the
system’s response x(t) may be interpreted as being the weighted superposition
Trang 8of past input f( ) values ‘weighted’ or multiplied by In other words,
to find the response x(t0) for some t=t0, we form the function and weshift it to ; the area of the product yields x(t0).
In the foregoing discussion we have assumed that the force f(t) starts at t=0; since this may not be case and f(t) can extend to negative values of t,
we can write eq (5.17) in the more general form
(5.20)
In order for a constant-parameter linear system to be physically realizable
(causal), it is necessary that it responds only to past inputs; this requires
(5.21)
In fact, if we recall that is the response to an impulse applied at time (i.e ), for (i.e ) there is no response because noimpulse has been applied This justifies eq (5.21) and allows us to extend theupper limit of integration in eq (5.20) from without changingthe result; we can then write
(5.22)
We note in passing that a physical system is always causal if the
independent variable is the real time t; however, not all physical systems are
causal (for example, if the independent variable is a space variable).Consider now, in eq (5.20), the change of variable obtained by defining where can be interpreted as the time delay between the occurrence
of the input and the instant when its result is calculated; we get
where the minus sign in the second integral comes from the fact that
Changing over the limits of integration to dispense with the minussign we get
(5.23)
which is an alternative form of the convolution integral
Trang 9Another alternative form can be obtained either by putting in eq(5.20) or by noting—in the second integral of eq (5.23)—that for since there is no response before the impulse occurs: this yields
(5.24)
The equality between the two integrals is obvious and in the last expression
we have used the common symbol * to indicate the convolution betweentwo functions Equation (5.24) is the most general form of the convolutionintegral for our purposes
An analogous line of reasoning, starting from eq (5.17) leads to
(5.25)
which, with eq (5.24), shows the symmetry of the convolution integral in
the excitation f(t) and the impulse response h(t) Simplicity suggests that the
simpler of the two functions be shifted in performing the calculations
A constant-parameter linear system is stable if any possible bounded input
produces a bounded output Since
(5.26)
if the input is bounded, i.e there exists some finite constant K such that
(5.27)then
(5.28)
It follows that if the impulse response function is absolutely integrable, i.e
(5.29)
then the output will be bounded and the system is stable Note that x(t) does
not need to satisfy
Trang 10which is necessary in the classical Fourier transform (frequency response)approach
A final comment to show the important property of frequency preservation
in linear systems Let h(t) be the impulse response of a constant-parameter linear system; for an arbitrary, well behaved input f(t) the nth derivative of the output x(t) is given by
(5.31)
If we assume a sinusoidal input of the general form weobtain, for example, for its second derivative Insertingthis result in eq (5.31) we get
(5.32)
so that x(t) must be sinusoidal with the same frequency as f (t) It follows
that a constant-parameter linear system cannot cause any frequencytranslation, but can only modify the amplitude and phase of an appliedinput
Example 5.2 Let us now determine the response of a damped system to the step function given by eq (5.33), which is often called the Heaviside function
when f0=1 In real situations this could model some kind of machine operation
or a car running over a surface that changes level abruptly (i.e a curb)
(5.33)
For assuming that the system starts from rest, the response can bewritten as the convolution integral
(5.34)which can be easily calculated if we remember that
Trang 11Since and after some manipulations we get
The initial conditions x(0)=0 and (0)=0 give for the constants
which, after substitution in eq (5.37) and a little algebra, give exactly thesolution of eq (5.35) Figure 5.3 is a graph of eq (5.35) with: f0=50 N, k=1000
For an undamped system eq (5.37) becomes
(5.38)
The response to a unit step input (sometimes called indicial response) and
the unit step function (Heaviside) itself are also very important in linearvibration theory and are often indicated with a symbol of their own: as wedid in Chapter 2, we will write θ(t) for the Heaviside function applied at t=0 while we will use the symbol s(t) for the response to a Heaviside input We
can write symbolically eq (4.13) for our SDOF linear system as
(5.39)
Trang 12where D is the linear differential operator
(5.40)Following this notation, we can then write the symbolic relations
(5.41)
and since—in the sense of distributions (Chapter 2)—it can be shown that
it is left to the reader to determine the following important relations betweenthe impulse response and the Heaviside response
(5.42)
which can be verified in eqs (5.7a), (5.35) and (5.38) (see also eq (5.34))
Fig 5.3 Response to step function.
Trang 13Two more examples will now show further applications of what has beensaid up to this point Both examples refer to an undamped SDOF system,since this system is often considered—for comparison purposes—in the
analysis of shock loading In these cases, the excitation is short compared to
the natural period of the structure and as a result, the response is notsignificantly influenced by the presence of damping We point out that theresponse of structures to shock is vital in design, particularly preliminarydesign, to select the system’s parameters in a manner that limits within aspecified range a certain response quantity—e.g maximum responseamplitude, maximum stress etc.—in order to prevent undesired vibration or
damage of the structure The concept of shock (or response) spectrum has
been devised to deal with these problems and, due to its importance, it will
be considered separately in the following section
Example 5.3 The first example is the response to a rectangular pulse of
duration t1 and amplitude f0 This problem has already been considered inExample 5.1 (eqs (5.10) and (5.11)), but now we proceed from eq (5.11) bysubstituting the appropriate initial conditions (5.12) to obtain an explicit
expression for the ‘free vibration era’ t>t1 The substitution gives
which, after some manipulations, yields the response for t>t1
(5.43)
Alternatively, the rectangular pulse f(t) can be seen as the superposition
of two step functions, i.e where f1(t) is given by eq (5.8),
f2(t) is a step of magnitude –f0 applied at t=t1 and the response can bedetermined accordingly as a superposition of the two responses Needless tosay, the results are again eq (5.10) for the ‘forced vibration era’ and eq (5.43)for the ‘free vibration era’ The reader is invited to draw a graph of the
response for different values of t1
Example 5.4 In this second example we consider the response of an
undamped system to a half-sine shock excitation, that is, to an excitationfunction of the form
(5.44)
Trang 14During the ‘forced vibration era’ the exciting function is asinusoid with circular frequency In order to calculate the
response, we notice that f(t) can be written in phasor form as if weagree to take the imaginary part as described in Chapter 1 (recall thatthe form of the exponential and the choice of the real or imaginary part
is a matter of convenience, it is only important to be consistent) Theresponse is then given by
and the integral can be easily solved using again
calculation of the definite integral in brackets yields
Taking the imaginary part of the expression above we get the system’sresponse for which is
(5.45)
The response in the ‘free vibration era’ (t>t1) is obtained from eq (4.8) with initial conditions that are determined by the state of the system at t=t1:this is
(5.46)where now
(5.47)
Trang 15Substitution of eqs (5.47) into eq (5.46)—considering that —yields
(5.48)
Figures 5.4(a) and 5.4(b) illustrate how the same undamped SDOF system
responds to two different half-sine excitations
Fig 5.4 Undamped SDOF system—half-sine response (a)
(b)
Trang 16Both the excitation and the response are shown in the two graphs even if themeasurement units are obviously different (newtons for the excitation functionand metres for the response displacement function).
maximum value plotted as a function of t1/T or, alternatively, as a function
of ωn /ω when the quantity ω (frequency of the exciting pulse) can be defined.
Such curves, extensively used in engineering practice, are called response
or shock spectra Several kinds of maxima are important, but in general the so-called maximax response is considered, which is the maximum of the
response attained at any time following the onset of the shock pulse
Mathematically speaking, given an exciting force f(t) of duration t1, wewant to determine the quantity
(5.49)
Let us consider a rectangular pulse of amplitude f0 and duration t1 Theresponse to such excitation is given by eqs (5.10) and (5.43) in the ‘forced’and ‘free’ vibration era, respectively The maximum value of response will
be attained in either the first or second era, depending on the value of t1:
when t<t1, equating the derivative of eq (5.10) to zero gives the condition
which is verified at a time t m given by provided that
(5.50)
where n is an integer and we have taken n=1 because we are interested in the
first maximum and we know that Substitution of t m in eq (5.10)gives the maximum value
Trang 17and this result can be stated by saying that the maximum value of the ratio
of dynamic response to static deformation (maximum dynamic magnification factor) is equal to 2.
In the free vibration era the response is given by eq (5.43) Equating itsderivative to zero gives the condition
which—considering again the first maximum—is verified at a time t m given by
The response spectrum for a rectangular pulse excitation is then obtained
by combining eqs (5.51) and (5.53) and is shown in Fig 5.5
We turn now to the half-sine excitation considered in Example 5.4 Theresponse to this kind of pulse is given by eqs (5.45) and (5.48) for the forcedand free vibration era, respectively and, once again, the maximum value can
be attained for or t>t1, depending on the value of t1 The two casesare illustrated in Figs 5.4(a) and 5.4(b)
Let us suppose that the maximum response occurs in the forced vibrationera; equating the derivative of eq (5.45) to zero gives
which is satisfied at a time t m determined by
(5.54)
Trang 18The first maximum is attained by considering the minus sign and n=1 in
eq (5.54) and we get
(5.55)
provided that which means (or ) if we remember that
and hence Substitution of eq (5.55) in eq(5.45) yields after some manipulation
(5.56a)
or, defining
(5.56b)
So, for example, if it follows and the maximum value
of the dynamic magnification factor D is given by
Fig 5.5 Rectangular pulse—shock spectrum.
Trang 19If the maximum occurs for t>t1, equating the derivative of eq (5.48) tozero leads to
which is satisfied at the time t m given by
(5.57a) (5.57b)
provided that i.e (or) and we have considered the
first maximum (n=1 and the minus sign) passing from eq (5.57a) to eq (5.57b) Substitution of the explicit expression for t m in eq (5.48) yields for themaximum value of displacement
(5.58a)
or, as a function of
(5.58b)for example, if the maximum value of D is found to be
The shock spectrum for a half-sine pulse excitation is shown in Fig 5.6,
where D max is plotted as a function of t1/T.
At resonance, i.e when (or), the expressions given byeqs (5.56a or 5.56b) and (5.58a or 5.58b) become indeterminate but the value of
D max can be obtained by calculating the limit for and using L’Hospital’srule in either one of the above equations It is not difficult to show that
Trang 20Following a similar line of reasoning, shock spectra for other impulsiveloading conditions can be worked out (e.g Harris [2], Jacobsen [3]).The calculations become more and more laborious, especially if damping
is taken into account, and other techniques are available (for example theLaplace transform, which will be considered later, and the plane-phase orother graphical methods), but often one has to make use of a computer for
an extensive investigation of the problem
However, the following general conclusions can be drawn for step-typeand pulse-type excitations, where damping is of relatively less importanceunless the system is highly damped
The excitation—a function of time only—may be a force applied to themass (as in the examples above) or a ground motion acting on the springanchorage The ground motion, in its turn, can be in the form of displacement,velocity or acceleration All these cases are mathematically similar and thegeneral equation
(5.59)
can be used, where v and ξ are the response and the excitation, respectively,
in the appropriate form For example, if y(t) is the ground displacement with
respect to a fixed frame of reference, the equation of motion is (4.55) with
c=0, i.e.
Fig 5.6 Half-sine pulse—shock spectrum.
Trang 21which, differentiating twice with respect to time, can be rearranged to
and can be treated as a second-order equation in when the ground
acceleration ÿ(t) is given Note the formal analogy with eq (5.59) where v=
and
For step-type excitations x max occurs after the step has risen to its full
value (t1 being the rise time) and the extreme values of D max are 1 and 2
As the ratio t1/T approaches zero, D max approaches the upper limit of 2;
when t1/T approaches infinity (low rise time compared to the system’s natural period), the step loses its character of dynamic excitation and D max approaches the lower limit of 1, which means that x max tends to the static
value f0/k.
The reader is invited to verify that for some shapes of the step rise time,
D max is equal to unity at certain finite values of t1/T: for example, for a step with constant slope rise, D max=1 when Different values
are obtained for different shapes of the slope, but the minimum value of t1/
T for which this occurs is 1 When D max=1, the amplitude of motion with
respect to the final value of the excitation as a base (the so-called residual response) is zero and this fact is sometimes exploited in the practical design
situation in order to achieve the smallest possible residual response
For pulse-type excitations, when the ratio of pulse duration to system
natural period t1/T is less than 1/2, the shape of certain types of pulses of
equal area (equal impulse) is of secondary significance in determining themaxima of the system’s response If the pulse shape has littlesignificance in almost all cases; only when must the pulse shape
be considered carefully Furthermore, the maximum response usually occursfor and D max has values between 1.5 and 1.8 If the pulse has
a vertical rise, D max attains asymptotically the value of 2 and in the particular
case of rectangular pulse D max=2 for
Again, the reader is invited to verify that the residual response amplitude
is zero for certain values of t1/T and if the pulse has a vertical rise or a vertical
decay (but not both) there are no zero values except at In the case
of a rectangular pulse, the residual response is zero for As
an example, Fig 5.7 shows the response of the undamped SDOF to a
rectangular pulse of duration t1=4 s in the case of
Note that Fig 5.7 illustrates a particular case; for different values of
t1/T the oscillation of the system continues after the end of the pulse with
Trang 22amplitude characteristics that depend on the value of t1/T considered in the
specific case under study
For several shapes of pulse the minimum value of t1/T for zero residual
response is 1 and occurs for an exciting rectangular pulse; for a sine pulsethe lowest value for zero residual response is and for a symmetricaltriangular pulse is
transforms
Fourier analysis is a mathematical technique that deals with the addition ofseveral harmonic oscillations to form a resultant and with the oppositeproblem Any branch of physical sciences in which harmonically varyingquantities play a part makes use of the theory of Fourier analysis at somestage of its theoretical development The subject of engineering vibrations is
no exception, and we have already given a review of the fundamentalmathematical aspects in Chapter 2 We move on from there, recalling some
of these fundamentals when needed in the course of our investigation Withrespect to Chapter 2, small differences in notation will be noted in a fewcases They have been adopted to suit our present needs and, in any case,are irrelevant to the essence of the discussion as long as consistency ismaintained from the beginning to the end of the specific argument beingdiscussed
Fig 5.7 Rectangular pulse response .
Trang 235.3.1 Response to periodic excitation
A periodic signal is a particular type of deterministic (i.e that can be expressed
by an explicit mathematical relationship) signal that repeats itself in time
every T seconds; T is called the period and for all values of t
where n=1, 2, 3, ··· Provided that the fluctuations in f(t) are not too
pathological, a periodic function can be represented by a convergent series
of harmonic functions whose frequencies are integral multiples of a certainfundamental frequency
A periodic exciting function f(t) (written in the form of a force for our
present convenience) can be written as
establish the relation between eqs (5.60a) and (5.60b), and
give the relation between eq (5.60a) and the complex form
If all the Cs are real, then all the bs are zero, f(t) is real and an even function of t, i.e f(–t)=f(t); if (i.e all as and bs are real, as in our case), then f(t) is real but not necessarily symmetrical about t=0 We point
Trang 24out that eq (5.60c) is not a phasor representation of the input signal (thesecond expression of eq (5.60b) is!), it is a different way of writing the periodic
function f(t) in its own right, where no convention of taking only the real or
imaginary part is implied
The conditions for the convergence of the series are extremely generaland cover the majority of engineering situations; one important restriction
to be kept in mind is that, when f(t) is discontinuous, the series gives the
average value of f(t) at the discontinuity The Fourier coefficients of the
series are given by (eq (2.6b) or (2.10))
(5.61)
for the expression of eq (5.60a) and
(5.62)
for the complex representation of eq (5.60c)
The mean (over one period) and mean-square values of f(t) and of its time
derivative can be expressed in terms of the Fourier coefficients as (Parseval’stheorem)
Trang 25Under such an excitation, we have the equation of motion for our dampedSDOF system
Alternatively, if the excitation is written in the more compact form of eq
(5.60c), x2 too can be taken in the form of a series with summation from –
to + Since we have determined in Chapter 4 (eqs (4.48) and (4.92)) thatthe steady-state response of our system to a sinusoidal load is written
(5.68)
where H(ω0) is the complex frequency response function (receptance in this
case, see also subsequent sections) and is given by
(5.69)
the response to our periodic load can be written as
(5.70)
Trang 26from which it follows that
(5.71)
The complementary function x1(t) must be added to eq (5.66) or (5.70) in
order to obtain the general solution Again (Chapter4),the complementary function dies out with time and contains two arbitraryconstants that must be determined by the initial conditions From thediscussion above we see that if the frequency of one of the harmonics in theexcitation is close to the system’s natural frequency ωn , its contribution to
the response will be relatively large (especially for light damping) and acondition of resonance may exist when for some value of n (it is clear from the context, but we note that the subscript n in ωn is for ‘natural’
frequency of the system and is not an integer n=1, 2, 3, ···)·
The undamped case can be easily obtained as a particular case of the
equations above with c=0.
5.3.2 Transform methods I: preliminary remarks
All the problems of transient response that we have considered up to thepresent can be solved by means of other methods by, so to speak, looking atthem from a different angle These techniques—which involve integraltransforms—may seem only mathematical complications when applied torelatively simple cases but their usefulness and power become clear whenmore complicated problems of nonperiodic excitations are encountered.Nonperiodic signals cannot be represented in terms of a fundamentalcomponent plus a sequence of harmonics, but must be considered as asuperposition of signals of all frequencies In other words, the series must begeneralized into an integral over all values of ω In Chapter 2 we introduced
the Fourier transform of a function y(t) as (eq (2.16))
(5.72)and the inverse Fourier transform (Fourier integral representation) as
(5.73)
Equation (5.73) represents the synthesis of y(t) from complex exponential harmonics while eq (5.72) represents analysis of y(t) into its frequency components, each frequency having for its amplitude the magnitude |Y( ω)|