Bài tập phần điện, vật lý đại cương, khoa Vật lý, Đại học sư phạm

Hai quả cầu mang điện có bán kính và khối lượng bằng nhau được treo ở hai đầu sợi dây có chiều dài bằng nhau. Người ta nhúng chúng vào một chất điện môi ( dầu) có khối lượng riêng p1 và hằng số điện môi e. Hỏi khối lượng riêng của hai quả cầu p phải bằng bao nhiêu để góc giữa các sợi dây trong không khí và trong chất điện môi là như nhau

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1 1

1 1

1

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k C k

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k

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1 1 1

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1kCkCkCCkkC

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E

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1

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r dS

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h

0 h

ε

εε

εππεε

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R2

E1dE

E

εε

R

R h R

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−

−

=

32

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ε

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=

hX 4 , = q O 5 , :ε /? & > % $> ()Y ) ,, " $> B((i ' @

1200 5

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=

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10.5,0

10.10.86,8

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300 1

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# HM , ε Y)* b L = > S % $> X , , " $# $

\ 9 X , ' &" 3L $# /)B ( (1r B

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k & & ' !% &' % $> * z / : C B? l% 8 ,

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10.5.10.6.10.86,8.17.2

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1111

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t

t t

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m A x

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(A/m)

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h R

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h R IR

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r

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l r

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dl I dH r

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4

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; 2

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r

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dr Rr

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3

03,0.10.100.3

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rR

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(A/m)

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10.100

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5

dS.BSd.B

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lrlln2

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0

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02,0.30.10

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4 4 cos 10 6 ,

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d H

1

I r H

1 2

. π

2

2 2

2 2

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R

Ir r R

I r

r H

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π

2 2

10 5

2 2

2

−

−π

i; B * @ H 16(A/m)

10 5 2

5 2

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=

=

i i

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B

1

0 2πµ

10 10 4 2

R R

0

R

Rln.2

Ildr

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IdS

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2

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(Wb)

10.8,71

50ln2

1.10.10

3 , 0

2