R E S E A R C H Open AccessExistence of a positive solution for quasilinear elliptic equations with nonlinearity including the gradient Mieko Tanaka* * Correspondence: tanaka@ma.kagu.tus
Trang 1R E S E A R C H Open Access
Existence of a positive solution for quasilinear elliptic equations with nonlinearity including
the gradient
Mieko Tanaka*
* Correspondence:
tanaka@ma.kagu.tus.ac.jp
Department of Mathematics, Tokyo
University of Science,
Kagurazaka 1-3, Shinjyuku-ku, Tokyo
162-8601, Japan
Abstract
We provide the existence of a positive solution for the quasilinear elliptic equation – div(a(x, |∇u|)∇u)= f (x, u, ∇u)
inunder the Dirichlet boundary condition As a special case (a(x, t) = t p–2), our
equation coincides with the usual p-Laplace equation The solution is established as
the limit of a sequence of positive solutions of approximate equations The positivity
of our solution follows from the behavior of f (x, tξ) as t is small In this paper, we do not impose the sign condition to the nonlinear term f
MSC: 35J92; 35P30 Keywords: nonhomogeneous elliptic operator; positive solution; the first
eigenvalue with weight; approximation
1 Introduction
In this paper, we consider the existence of a positive solution for the following quasilinear elliptic equation:
⎧
⎨
⎩
– div A(x, ∇u) = f (x, u, ∇u) in ,
where ⊂ R N is a bounded domain with Cboundary∂ Here, A: × R N → RN is
a map which is strictly monotone in the second variable and satisfies certain regularity
conditions (see the following assumption (A)) Equation (P) contains the corresponding
p-Laplacian problem as a special case However, in general, we do not suppose that this
operator is (p – )-homogeneous in the second variable.
Throughout this paper, we assume that the map A and the nonlinear term f satisfy the following assumptions (A) and (f ), respectively.
(A) A(x, y) = a(x, |y|)y, where a(x, t) > for all (x, t) ∈ × (, +∞), and there exist positive constants C, C, C, C, < t≤ and < p < ∞ such that
(i) A ∈ C( × R N,RN)∩ C( × (R N\ {}), RN);
(ii) |D y A(x, y) | ≤ C|y| p– for every x ∈ , and y ∈ R N\ {};
(iii) D y A(x, y)ξ · ξ ≥ C|y| p– |ξ|for every x ∈ , y ∈ R N \ {} and ξ ∈ R N;
© 2013 Tanaka; licensee Springer This is an Open Access article distributed under the terms of the Creative Commons Attribu-tion License (http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribuAttribu-tion, and reproducAttribu-tion in any medium, provided the original work is properly cited.
Trang 2(iv) |D x A(x, y) | ≤ C( +|y| p– ) for every x ∈ , y ∈ R N\ {};
(v) |D x A(x, y) | ≤ C|y| p–(– log|y|) for every x ∈ , y ∈ R N with <|y| < t
(f ) f is a continuous function on × [, ∞) × R N satisfying f (x, , ξ) = for every
(x, ξ) ∈ × R N and the following growth condition: there exist < q < p, b> and
a continuous function fon × [, ∞) such that
–b
+ t q–
≤ f(x, t) ≤ f (x, t, ξ) ≤ b
+ t q–+|ξ| q–
()
for every (x, t, ξ) ∈ × [, ∞) × R N
In this paper, we say that u ∈ W ,p
() is a (weak) solution of (P) if
A(x, ∇u)∇ϕ dx =
f (x, u, ∇u)ϕ dx
for allϕ ∈ W ,p
().
A similar hypothesis to (A) is considered in the study of quasilinear elliptic problems (see
[, Example ..], [–] and also refer to [, ] for the generalized p-Laplace operators).
From now on, we assume that C≤ p – ≤ C, which is without any loss of generality as
can be seen from assumptions (A)(ii), (iii)
In particular, for A(x, y) = |y| p– y, that is, div A(x, ∇u) stands for the usual p-Laplacian
p u, we can take C= C= p – in (A) Conversely, in the case where C= C= p –
holds in (A), by the inequalities in Remark (ii) and (iii), we see that a(x, t) = |t| p–whence
A(x, y) = |y| p– y Hence, our equation contains the p-Laplace equation as a special case.
In the case where f does not depend on the gradient of u, there are many existence results because our equation has the variational structure (cf [, , ]) Although there are
a few results for our equation (P) with f including ∇u, we can refer to [, ] and [] for the
existence of a positive solution in the case of the (p, q)-Laplacian or m-Laplacian ( < m <
N ) In particular, in [] and [], the nonlinear term f is imposed to be nonnegative The
results in [] and [] are applied to the m-Laplace equation with an (m – )-superlinear
term f w.r.t u Here, we mention the result in [] for the p-Laplacian Faria, Miyagaki
and Motreanu considered the case where f is (p – )-sublinear w.r.t u and ∇u, and they
supposed that f (x, u, ∇u) ≥ cu r for some c > and < r < p – The purpose of this paper
is to remove the sign condition and to admit the condition like f (x, u, ∇u) ≥ λu p– + o(u p–)
for largeλ > as u → + Concerning the condition for f as |u| → , Zou in [] imposed
that there exists an L > satisfying f (x, u, ∇u) = Lu m– +o(|u| m–+|∇u|m–) as|u|, |∇u| →
for the m-Laplace problem Hence, we cannot apply the result of [] and [] to the case of
f (x, u, ∇u) = λm(x)u p– + ( – u p–)|∇u| r– + o(u p– ) as u → + for < r < p and m ∈ L∞()
(admitting sign changes), but we can do our result ifλ > is large.
In [], the positivity of a solution is proved by the comparison principle However, since
we are not able to do it for our operator in general, after we provide a non-negative and
non-trivial solution as a limit of positive approximate solutions (in Section ), we obtain
the positivity of it due to the strong maximum principle for our operator
1.1 Statements
To state our first result, we define a positive constant A pby
A p:= C
p –
C
C
p–
Trang 3which is equal to in the case of A(x, y) = |y| p– y (i.e., the case of the p-Laplacian) because
we can choose C= C= p – Then, we introduce the hypothesis (f) to the function
f(x, t) in (f ) as t is small.
(f) There exist m ∈ L∞() and b>μ(m)A psuch that the Lebesgue measure of
{x ∈ ; m(x) > } is positive and
lim inf
t→+
f(x, t)
where fis the continuous function in (f ) andμ(m) is the first positive eigenvalue
of the p-Laplacian with the weight function m obtained by
μ(m) := inf
|∇u| p dx; u ∈ W ,p
() and
m |u| p dx =
Theorem Assume (f) Then equation (P) has a positive solution u ∈ int P, where
P :=
u ∈ C
(); u(x) ≥ in , intP :=
u ∈ C
(); u(x) > in and ∂u/∂ν < on ∂ ,
Next, we consider the case where A is asymptotically (p – )-homogeneous near zero in
the following sense:
(AH) There exist a positive function a∈ C(, (, +∞)) and
a(x, t) ∈ C( × [, +∞), R) such that
A(x, y) = a(x)|y| p– y + a
x, |y|y for every x ∈ , y ∈ R N and ()
lim
t→+
a(x, t)
Under (AH), we can replace the hypothesis (f) with the following (f):
(f) There exist m ∈ L∞() and b>λ(m) such that () and the Lebesgue measure of {x ∈ ; m(x) > } is positive, where λ(m) is the first positive eigenvalue of – div(a(x)|∇u| p– ∇u) with a weight function m obtained by
λ(m) := inf
a(x) |∇u| p dx; u ∈ W ,p
() and
m |u| p dx =
Theorem Assume (AH) and (f) Then equation (P) has a positive solution u ∈ int P.
Throughout this paper, we may assume that f (x, t, ξ) = for every t ≤ , x ∈ and ξ ∈
RN because we consider the existence of a positive solution only In what follows, the
norm on W,p( p, where q denotes the usual norm of L q()
for u ∈ L q() ( ≤ q ≤ ∞) Moreover, we denote u±:= max{±u, }.
1.2 Properties of the mapA
Remark The following assertions hold under condition (A):
(i) for all x ∈ , A(x, y) is maximal monotone and strictly monotone in y;
(ii) |A(x, y)| ≤ C|y| p– for every (x, y) ∈ × R N;
Trang 4(iii) A(x, y)y≥ C
p– |y| p for every (x, y) ∈ × R N,
where Cand Care the positive constants in (A)
Proposition ([, Proposition ]) Let A: W ,p
() → W ,p
()∗be a map defined by
A(u), v
=
A(x, ∇u)∇v dx
for u, v ∈ W ,p
prop-erty, that is, any sequence {u n } weakly convergent to u with lim sup n→∞A(u n ), u n – u
strongly converges to u.
2 Constructing approximate solutions
Choose a function ψ ∈ P \ {} In this section, for such ψ and ε > , we consider the
following elliptic equation:
⎧
⎨
⎩
– div A(x, ∇u) = f (x, u, ∇u) + εψ(x) in ,
In [], the caseψ ≡ in the above equation is considered.
Lemma Suppose (f) or (f) Then there exists λ> such that f (x, t, ξ)t + λt p ≥ for
every x ∈ , t ≥ and ξ ∈ R N
Proof From the growth condition of fand (), it follows that
f(x, t)t ≥ –b ∞t p – bt p for every (x, t) ∈ × [, ∞)
holds, where bis a positive constant independent of (x, t) Therefore, for λ≥ b ∞+
b, we easily see that f (x, t, ξ)t +λt p ≥ f(x, t)t + λt p ≥ for every x ∈ , t ≥ and ξ ∈ R N
Proposition If u ε ∈ W ,p
() is a non-negative solution of (P; ε) for ε ≥ , then u ε∈
L∞() Moreover, for any ε> , there exists a positive constant D > such that ε ∞≤
Proof Set p∗= Np/(N – p) if N > p, and in the case of N ≤ p, p∗> p is an arbitrarily fixed
constant Let u ε be a non-negative solution of (P; ε) with ≤ ε ≤ ε(someε> ) For
r > , choose a smooth increasing function η(t) such that η(t) = t r+if ≤ t ≤ , η(t) =
dt if t ≥ d andη(t) ≥ d> if ≤ t ≤ d for some < d< < d, d Defineξ M (u) :=
M r+ η(u/M) for M > .
If u ε ∈ L r+p(), then by taking ξ M (u ε) as a test function (note thatηis bounded), we have
C
p –
|∇u ε|p ξ
M (u ε ) dx
≤
A(x, ∇u ε)∇uε ξ
M (u ε ) dx
Trang 5
f (x, u ε,∇u ε) +εψξ M (u ε ) dx
≤ b
+ u q– ε +ε ∞
M r+ η(u ε /M) dx + b
|∇u ε|q– ξ M (u ε ) dx
≤ dd
b+ε ∞
ε r+q r+q+ ε r+ r+
+ b
|∇u ε|q– ξ M (u ε ) dx ()
due to Remark (iii) and M r+ η(t/M) ≤ ddt r+ Putting β := p/(p – q + ) < p, we see
that (ξ M (u ε))/(ξ
M (u ε))(q–)/p = u r+
ε /((r + )u r
ε)(q–)/p ≤ u +r/ β
ε provided < u ε < M (note
r > ) Similarly, if M ≤ u ε ≤ dM, then ( ξ M (u ε))/(ξ
M (u ε))(q–)/p ≤ ddM r+ /(dM r)(q–)/p=
ddd (–q)/p M +r/ β ≤ ddd (–q)/p u +r/ β
ε , and if u ε > dM, then (ξ M (u ε))/(ξ
M (u ε))(q–)/p=
d/β M r/β u ε ≤ d/β
u +r/ β
ε (note d> ) Thus, according to Young’s inequality, for everyδ > ,
there exists C δ> such that
|∇u ε|q– ξ M (u ε ) dx ≤ δ
|∇u ε|p ξ
M (u ε ) dx + C δ
u ε>
(ξ M (u ε))β (ξ
M (u ε))(q–) β/p dx
≤ δ
|∇u ε|p ξ
M (u ε ) dx + C δ d
u r+β ε dx, () whereβ := p/(p – q + ) < p and d= max{ddd (–q)/p , d/β} (> ) As a result, because of
r + p > r + q, r + β, according to Hölder’s inequality and the monotonicity of t rwith respect
to r on [, ∞), taking a < δ < C/b(p – ) and setting u M
ε (x) := min {u ε (x), M}, we obtain
b
rp
max
, ε r+p r+p ≥rp
|∇u ε|p ξ
M (u ε ) dx≥rp
∇u M ε p
u M εr
dx
=u M
εrp
≥ C∗u M
ε rp
¯p∗= C∗u M
εr+p
¯p∗r ()
provided u ε ∈ L r+p() by () and (), where r= + r/p, C∗ comes from the
continu-ous embedding of W,p() into L p∗
() and dis a positive constant independent of u ε,
ε and r Consequently, Moser’s iteration process implies our conclusion In fact, we
de-fine a sequence{r m}m by r:= p∗– p and r m+ := p∗(p + r m )/p – p Then, we see that u ε∈
L p∗(p+rm)/p
() = L p+r m+() holds if u ε ∈ L p+r m() by applying Fatou’s lemma to () and
letting M → ∞ Here, we also see r m+ = p∗r m /p + p∗– p ≥ (p∗/p) m+ r→ ∞ as m → ∞.
Therefore, by the same argument as in Theorem C in [], we can obtain u ε ∈ L∞() and
Lemma Suppose (f) or (f) If u ε ∈ W ,p
() is a solution of (P; ε) for ε > , then u ε ∈ int P.
Proof Taking –(u ε)–as a test function in (P; ε), we have
C
p – ∇(uε)–p
p≤
A(x, ∇u ε)
–∇(u ε)–
dx = – ε
ψ(u ε)–dx≤
because of f (x, t, ξ) = if t ≤ and by Remark (iii) Hence, u ε≥ follows Because
Propo-sition guarantees that u ε ∈ L∞(), we have u ε ∈ C,α
() (for some < α < ) by the
regu-larity result in [] Note that u ε ≡ because of ε > and ψ ≡ In addition, Lemma
im-plies the existence ofλ> such that – div A(x, ∇u ε) +λu p– ε ≥ in the distribution sense
Trang 6Therefore, according to Theorem A and Theorem B in [], u ε> in and ∂u ε/∂ν < on
The following result can be shown by the same argument as in [, Theorem .]
Proposition Suppose (f) or (f) Then, for every ε > , (P; ε) has a positive solution u ε∈
intP.
Proof Fix any ε > and let {e, , e m, } be a Schauder basis of W ,p
() (refer to
[] for the existence) For each m ∈ N, we define the m-dimensional subspace V m of
W,p() by V m:= lin.sp.{e, , e m } Moreover, set a linear isomorphism T m: Rm → V m
by T m(ξ, ,ξ m) :=m
i= ξ i e i ∈ V m , and let T m∗ : V m∗→ (Rm)∗be a dual map of T m By iden-tifyingRm and (Rm)∗, we may consider that T m∗ maps from V m∗ toRm Define maps A m
and B m from V m to V m∗ as follows:
A m (u), v
:=
A(x, ∇u)∇v dx and B m (u), v
:=
f (x, u, ∇u)v dx + ε
for u, v ∈ V m We claim that for every m ∈ N, there exists u m ∈ V m such that A m (u m) –
B m (u m ) = in V m∗ Indeed, by the growth condition of f , Remark (iii) and Hölder’s
in-equality, we easily have
A m (u) – B m (u), u
≥ C
p –
p – b
+ q q+ q– p β
for every u ∈ V m, whereβ = p/(p – q + ) < p This implies that A m – B m is coercive on V m
by q < p Set a homotopy H m (t, y) := ty + ( – t)T m∗(A m (T m (y)) – B m (T m (y))) for t∈ [, ] and
y∈ Rm By recalling that A m – B m is coercive on V m , we see that there exists an R > such
equivalent on V m Therefore, we have
= deg
I m , B R(),
= deg
H m(,·), B R(),
= deg
H m(,·), B R(),
= deg
T m∗◦ (A m – B m)◦ T m , B R(),
,
where I mis the identity map onRm , B R() :={y ∈ R m;|y| < R} and deg(g, B, ) denotes the
degree onRm for a continuous map g : B→ Rm (cf []) Hence, this yields the existence
of y m∈ Rm such that (T m∗◦ (A m – B m)◦ T m )(y m ) = , and so the desired u mis obtained by
setting u m = T m (y m)∈ V m since T m∗ is injective
Because () with u = u m ∈ W ,p
assume, by choosing a subsequence, that u m converges to some uweakly in W,p() and
strongly in L p() Let P m be a natural projection onto V m , that is, P m u =m
i= ξ i e i for u =
∞
i= ξ i e i Since u m , P m u∈ V m and A m (u m ) – B m (u m ) = in V m∗, by noting that A m = A on
V m for a map A defined in Proposition , we obtain
A(u m ), u m – u
+
A(u m ), u– P m u
=
A m (u m ), u m – P m u
=
B m (u m ), u m – P m u
Trang 7
f (x, u m,∇u m) +εψ(u m – u) dx
+
f (x, u m,∇u m) +εψ(u– P m u) dx→
()∗ is bounded, by the boundedness of m
∞ holds As a result, it follows from the (S)+property of A that u m → uin W,p() as
Finally, we shall prove that uis a solution of (P; ε) Fix any l ∈ N and ϕ ∈ V l For each
m ≥ l, by letting m → ∞ in A m (u m), m (u m),
A(x, ∇u)∇ϕ dx =
f (x, u,∇u)ϕ dx + ε
Since l is arbitrary, () holds for every ϕ ∈l≥V l Moreover, the density of
l≥V lin
W,p() guarantees that () holds for every ϕ ∈ W ,p
() This means that uis a solution
of (P; ε) Consequently, our conclusion u∈ int P follows from Lemma .
3 Proof of theorems
Lemma Let ϕ, u ∈ int P Then
A(x, ∇u)∇
ϕ p
u p–
holds, where A p is the positive constant defined by ().
Proof Because of ϕ, u ∈ int P, there exist δ>δ> such thatδu ≥ ϕ ≥ δu in Thus,
δ≥ ϕ/u ≥ δ and /δ≥ u/ϕ ≥ /δin Hence, u/ϕ, ϕ/u ∈ L∞() hold Therefore, we
have
ϕ p
u p–
= p
ϕ u
p–
A(x, ∇u)∇ϕ – (p – )
ϕ u
p
A(x, ∇u)∇u
≤ pC
p –
ϕ
u
p–
|∇u| p– |∇ϕ| – C
ϕ
u
p
|∇u| p
p –
/p ϕ
u |∇u|
p–
p
p –
/p
CC(–p)/p |∇ϕ|
– C
ϕ u
p
Lemma Assume that a∈ C(, [, ∞)) and let ϕ, u ∈ int P Then
a(x) |∇ϕ| p– ∇ϕ∇
ϕ p
– u p
ϕ p–
dx –
a(x) |∇u| p– ∇u∇
ϕ p
– u p
u p–
holds.
Trang 8Proof First, we note that u/ϕ, ϕ/u ∈ L∞() hold by the same reason as in Lemma
Ap-plying Young’s inequality to the second term of the right-hand side in () (refer to ()
with C= C= p – ), we obtain
a(x) |∇ϕ| p– ∇ϕ∇
ϕ p – u p
ϕ p–
≥ a(x)
|∇ϕ| p – p
u ϕ
p–
|∇ϕ| p– |∇u| + (p – )
u ϕ
p
|∇ϕ| p
()
≥ a(x)
|∇ϕ| p–|∇u| p
()
in Similarly, we also have
a(x)|∇u| p– ∇u∇
ϕ p
– u p
u p–
≤ a(x)
|∇ϕ| p–|∇u| p
Under (f) or (f), we denote a solution u ε ∈ int P of (P; ε) for each ε > obtained by
Proposition
Lemma Assume (f) or (f) Let I := (, ] Then {u ε}ε∈I is bounded in W,p().
Proof Taking u ε as a test function in (P; ε), we have
C
p
p≤
A(x, ∇u ε)∇uε dx =
f (x, u ε,∇u ε )u ε dx + ε
ψu ε dx
≤ b
ε + ε q
q+ ε q–
p ε β
≤ b
ε ε q
by Remark (iii), the growth condition of f , Hölder’s inequality and the continuity of the
embedding of W,p() into L p(), where β = p/(p–q+) (< p) and b
is a positive constant
independent of u ε Because of q < p, this yields the boundedness of ε ε p)
Lemma Assume (f) or (f) Then |∇u ε |/u ε ∈ L p( ε |/u ε p p ≤ λ||/Chold
for every ε > , where || denotes the Lebesgue measure of , and where Cand λare
positive constants as in (A) and Lemma , respectively.
Proof Fix any ε > and choose any ρ > By taking (u ε+ρ) –pas a test function, we obtain
( – p)
A(x, ∇u ε)∇uε
(u ε+ρ) p dx =
f (x, u ε,∇u ε) +εψ
(u ε+ρ) p– dx ≥ –λ
u p– ε
(u ε+ρ) p– dx
by Lemma andεψ ≥ On the other hand, by Remark (iii) and – p < , we have
( – p)
A(x, ∇u ε)∇uε
(u ε+ρ) p dx ≤ –C
|∇u ε|p
Trang 9Therefore, () and () imply the inequality
|∇u ε|p /(u ε+ρ) p dx ≤ λ||/Cfor every
Lemma Assume (f) and (AH) Let ϕ ∈ int P If u ε → in C
() as ε → +, then
lim
ε→+
a
x, |∇u ε|∇u ε∇
ϕ p
– u p ε
u p– ε
dx
=
holds, where ais a continuous function as in (AH).
Proof Note that u ε/ϕ, ϕ/u ε ∈ L∞() hold (as in the proof of Lemma ) Because we easily
see that| a(x, |∇u|)|∇u|dx p p for every u ∈ W ,p
() with some C >
inde-pendent of u (see ()), it is sufficient to show| a(x, |∇u ε |)∇u ε ∇(ϕ p /u p– ε ) dx| → as
ε → + Here, we fix any δ > By the property of a(see ()) and because we are
assum-ing that u ε → in C
() as ε → +, we have |a(x, |∇u ε |)| ≤ δ|∇u ε|p– for every x ∈
provided sufficiently smallε > Therefore, for such sufficiently small ε > , we obtain
a
x, |∇u ε|∇u ε∇
ϕ p
u p– ε
dx
≤ p
|a(x, |∇u ε |)||∇u ε ||∇ϕ|ϕ p–
|a(x, |∇u ε |)||∇u ε|ϕ p
p
C() p
|∇u ε|
u ε
p–
dx + (p – )
|∇u ε|
u ε
p
dx
p
C
() ||p( λ/C)–/p + (p – )( λ/C) because of |∇u ε |/u ε ∈ L p() by Lemma Since δ > is arbitrary, our conclusion is
3.1 Proof of main results
Proof of Theorems
independent ofε ∈ (, ] Hence, there exist M> and <α < such that u ε ∈ C,α
() and
ε C,α
() ≤ Mfor everyε ∈ (, ] by the regularity result in [] Because the embedding
of C,α() into C
() is compact and by u ε ∈ int P, there exists a sequence {ε n } and u∈ P
such thatε n → + and u n := u ε n → uin C() as n → ∞ If u= occurs, then u∈
shall prove u= by contradiction for each theorem So, we suppose that u= , whence
u n → in C
() as n → ∞.
eigenvalueμ(m) (cf [, ], it is well known that we can obtain ϕ as the minimizer of ()),
namely,ϕ is a positive solution of – p u = μ(m)m(x)|u| p– u in and u = on ∂ Since
p-Laplacian is (p – )-homogeneous, we may assume that ϕ satisfies m(x)ϕ p dx = , and
hence p=μ(m)
m(x) ϕ p dx = μ(m) holds by taking ϕ as a test function Choose
ρ > satisfying b– A p μ(m) > p p (note that b– A p μ(m) > as in (f)) Due to (f),
there exists aδ > such that f(x, t) ≥ (bm(x) – ρ)t p–for every ≤ t ≤ δ and x ∈ Since
Trang 10we are assuming u n → in C
( n ∞≤ δ occurs for sufficiently large n.
Then, for such sufficiently large n, according to Lemma , () and ψ ≥ , we obtain
A p μ(m) = A p p p≥
A(x, ∇u n)∇
ϕ p
u p– n
dx =
f (x, u n,∇u n) +εψ
u p– n
ϕ p dx
≥
f(x, u n)
u p– n ϕ p dx ≥ b
m(x) ϕ p dx – p p = b– p p > A p μ(m).
Proof of Theorem Since∞ > supx ∈ a(x)≥ infx ∈ a(x) > holds, by the standard
ar-gument as in the p-Laplacian, we see that λ(m) > and it is the first positive eigenvalue
of – div(a(x) |∇u| p– ∇u) = λm(x)|u| p– u in and u = on ∂ Therefore, by the
well-known argument, there exists a positive eigenfunctionϕ∈ int P corresponding to λ(m)
(we can obtainϕ as the minimizer of ()) Hence, by takingϕ as a test function, we
have <
a(x) |∇ϕ|p dx = λ(m)
m(x) ϕ p
dx Thus,
m(x) ϕ p
dx > follows Because
u n ∈ int P is a solution of (P; ε n) andϕ∈ int P is an eigenfunction corresponding to λ(m),
according to Lemma and Lemma (note A(x, y) = a|y| p– y + a(x, |y|)y as in (AH)),
we obtain
≤
a(x)|∇ϕ|p– ∇ϕ∇
ϕ p
– u p n
ϕ p–
dx –
a(x)|∇u n|p– ∇u n∇
ϕ p
– u p n
u p– n
dx
≤ λ(m)
m
ϕ p
– u p n
dx –
f(x, u n)
u p– n
ϕ p
dx
+
a
x, |∇u n|∇u n∇
ϕ p
– u p n
u p– n
dx +
f (x, u n,∇u n )u n dx + ε n
ψu n dx
= –
f(x, u n)
u p– n
– bm(x)
ϕ p
dx –
b–λ(m)
m(x)ϕ p
as n → ∞ since we are assuming u n → in C
(), where we use the facts that ψ ≥ and
ϕ> in Furthermore, by Fatou’s lemma and (), we have
lim inf
n→∞
f(x, u n)
u p– n
– bm(x)
ϕ p
dx≥
As a result, by taking a limit superior with respect to n in (), we have ≤ –(b–
λ(m))
m(x)ϕ p
Competing interests
The author declares that she has no competing interests.
Acknowledgements
The author would like to express her sincere thanks to Professor Shizuo Miyajima for helpful comments and
encouragement The author thanks Professor Dumitru Motreanu for giving her the opportunity of this work The author
thanks referees for their helpful comments.
Received: 15 May 2013 Accepted: 10 July 2013 Published: 24 July 2013
... ε ≥ in the distribution sense Trang 6Therefore, according to Theorem A and Theorem...
Trang 8Proof First, we note that u/ϕ, ϕ/u ∈ L∞() hold by the same reason as in Lemma... m (u m ), u m – P m u
Trang 7