Motivated and inspired by the above results, in this paper, we introduce a new modified mixed Ishikawa iter-ative sequence with error for common fixed points of two more generalized asym
Trang 1Research Article
A Modified Mixed Ishikawa Iteration for
Common Fixed Points of Two Asymptotically Quasi
Pseudocontractive Type Non-Self-Mappings
Yuanheng Wang and Huimin Shi
Department of Mathematics, Zhejiang Normal University, Zhejiang 321004, China
Correspondence should be addressed to Yuanheng Wang; wangyuanhengmath@163.com
Received 3 January 2014; Accepted 21 February 2014; Published 26 March 2014
Academic Editor: Rudong Chen
Copyright © 2014 Y Wang and H Shi This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited
A new modified mixed Ishikawa iterative sequence with error for common fixed points of two asymptotically quasi pseudocontrac-tive type non-self-mappings is introduced By the flexible use of the iterapseudocontrac-tive scheme and a new lemma, some strong convergence theorems are proved under suitable conditions The results in this paper improve and generalize some existing results
1 Introduction
Let𝐸 be a real Banach space with its dual 𝐸∗and let𝐶 be a
nonempty, closed, and convex subset of𝐸 The mapping 𝐽 :
𝐸 → 2𝐸 ∗
is the normalized duality mapping defined by
𝐽 (𝑥) = {𝑥∗∈ 𝐸∗ : ⟨𝑥, 𝑥∗⟩ = ‖𝑥‖ ⋅ 𝑥∗,‖𝑥‖ = 𝑥∗},
𝑥 ∈ 𝐸 (1) Let𝑇 : 𝐶 → 𝐸 be a mapping We denote the fixed point
set of𝑇 by 𝐹(𝑇); that is, 𝐹(𝑇) = {𝑥 ∈ 𝐶 : 𝑥 = 𝑇𝑥} Recall that
a mapping𝑇 : 𝐶 → 𝐸 is said to be nonexpansive if, for each
𝑥, 𝑦 ∈ 𝐶,
𝑇𝑥 − 𝑇𝑦 ≤ 𝑥 − 𝑦 (2)
𝑇 is said to be asymptotically nonexpansive if there exists
a sequence𝑘𝑛 ⊆ [1, ∞) with 𝑘𝑛 → 1 as 𝑛 → ∞ such that
𝑇𝑛𝑥 − 𝑇𝑛𝑦 ≤ 𝑘𝑛𝑥 − 𝑦, ∀𝑥,𝑦 ∈ 𝐶 (3)
A sequence of self-mappings{𝑇𝑖}∞𝑖=1on𝐶 is said to be uniform
Lipschitzian with the coefficient𝐿 if, for any 𝑖 = 1, 2, , the
following holds:
𝑇𝑛
𝑖𝑥 − 𝑇𝑖𝑛𝑦 ≤ 𝐿𝑥 − 𝑦, ∀𝑥,𝑦 ∈ 𝐶 (4)
𝑇 is said to be asymptotically pseudocontractive if there exist𝑘𝑛 ⊆ [1, ∞) with 𝑘𝑛 → 1 as 𝑛 → ∞ and 𝑗(𝑥 − 𝑦) ∈ 𝐽(𝑥 − 𝑦) such that
⟨𝑇𝑛𝑥 − 𝑇𝑛𝑦, 𝑗 (𝑥 − 𝑦)⟩ ≤ 𝑘𝑛𝑥 − 𝑦2, ∀𝑥, 𝑦 ∈ 𝐶 (5)
It is obvious to see that every nonexpansive mapping
is asymptotically nonexpansive and every asymptotically nonexpansive mapping is asymptotically pseudocontractive Goebel and Kirk [1] introduced the class of asymptotically nonexpansive mappings in 1972 The class of asymptotically pseudocontractive mappings was introduced by Schu [2] and has been studied by various authors for its generalized mappings in Hilbert spaces, Banach spaces, or generalized topological vector spaces by using the modified Mann or Ishikawa iteration methods (see, e.g.,[3–21])
In 2003, Chidume et al [22] studied fixed points of an asymptotically nonexpansive non-self-mapping𝑇 : 𝐶 →
𝐸 and the strong convergence of an iterative sequence {𝑥𝑛} generated by
𝑥𝑛+1= 𝑃 ((1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇(𝑃𝑇)𝑛−1𝑥𝑛) , 𝑛 ≥ 1, 𝑥1∈ 𝐶,
(6) where𝑃 : 𝐸 → 𝐶 is a nonexpansive retraction
Abstract and Applied Analysis
Volume 2014, Article ID 129069, 7 pages
http://dx.doi.org/10.1155/2014/129069
Trang 2In 2011, Zegeye et al [23] proved a strong convergence of
Ishikawa scheme to a uniformly L-Lipschitzian and
asymp-totically pseudocontractive mappings in the intermediate
sense which satisfies the following inequality (see [24]):
lim sup
𝑛 → ∞ sup
𝑥,𝑦∈𝐶(⟨𝑇𝑛𝑥 − 𝑇𝑛𝑦, 𝑥 − 𝑦⟩ − 𝑘𝑛𝑥 − 𝑦2) ≤ 0,
∀𝑥, 𝑦 ∈ 𝐶,
(7)
where𝑘𝑛⊆ [1, ∞) with 𝑘𝑛 → 1 as 𝑛 → ∞
Motivated and inspired by the above results, in this
paper, we introduce a new modified mixed Ishikawa
iter-ative sequence with error for common fixed points of two
more generalized asymptotically quasi pseudocontractive
type non-self-mappings By the flexible use of the iterative
scheme and a new lemma (i.e., Lemma 6 in this paper),
under suitable conditions, we prove some strong convergence
theorems Our results extend and improve many results of
other authors to a certain extent, such as [6,8,14–23]
2 Preliminaries
Definition 1 Let𝐶 be a nonempty closed convex subset of a
real Banach space𝐸 𝐶 is said to be a nonexpansive retract
(with𝑃) of 𝐸 if there exists a nonexpansive mapping 𝑃 :
𝐸 → 𝐶 such that, for all 𝑥 ∈ 𝐶, 𝑃𝑥 = 𝑥 And 𝑃 is called
a nonexpansive retraction
Let 𝑇 : 𝐶 → 𝐸 be a non-mapping (maybe
self-mapping) 𝑇 is called uniformly L-Lipschitzian (with 𝑃) if
there exists a constant𝐿 > 0 such that
𝑇(𝑃𝑇)𝑛−1𝑥 − 𝑇(𝑃𝑇)𝑛−1𝑦 ≤ 𝐿𝑥 − 𝑦, ∀𝑥,𝑦 ∈ 𝐶, 𝑛 ≥ 1
(8)
𝑇 is said to be asymptotically pseudocontractive (with 𝑃)
if there exist𝑘𝑛 ⊆ [1, ∞) with 𝑘𝑛 → 1 as 𝑛 → ∞ and
∀𝑥, 𝑦 ∈ 𝐶, ∃𝑗(𝑥 − 𝑦) ∈ 𝐽(𝑥 − 𝑦) such that
⟨𝑇(𝑃𝑇)𝑛−1𝑥 − 𝑇(𝑃𝑇)𝑛−1𝑦, 𝑗 (𝑥 − 𝑦)⟩ ≤ 𝑘𝑛𝑥 − 𝑦2 (9)
𝑇 is said to be an asymptotically pseudocontractive type
(with𝑃) if there exist 𝑘𝑛 ⊆ [1, ∞) with 𝑘𝑛 → 1 as 𝑛 → ∞
and∀𝑥, 𝑦 ∈ 𝐶, 𝑗(𝑥 − 𝑦) ∈ 𝐽(𝑥 − 𝑦) such that
lim sup
𝑛 → ∞ sup
𝑥,𝑦∈𝐶 lim inf
𝑗(𝑥−𝑦)∈𝐽(𝑥−𝑦)(⟨𝑇(𝑃𝑇)𝑛−1𝑥 − 𝑇(𝑃𝑇)𝑛−1𝑦,
𝑗 (𝑥 − 𝑦)⟩ − 𝑘𝑛𝑥 − 𝑦2) ≤ 0
(10)
𝑇 is said to be an asymptotically quasi pseudocontractive
type (with𝑃) if 𝐹(𝑇) ̸= 0, for 𝑝 ∈ 𝐹(𝑇), there exist 𝑘𝑛⊆ [1, ∞)
with𝑘𝑛 → 1 as 𝑛 → ∞, and, ∀𝑥 ∈ 𝐶, 𝑗(𝑥 − 𝑝) ∈ 𝐽(𝑥 − 𝑝)
such that
lim sup
𝑛 → ∞ sup
𝑥∈𝐶 lim inf
𝑗(𝑥−𝑝)∈𝐽(𝑥−𝑝)(⟨𝑇(𝑃𝑇)𝑛−1𝑥 − 𝑝, 𝑗 (𝑥 − 𝑦)⟩
− 𝑘𝑛𝑥 − 𝑝2) ≤ 0
(11)
Remark 2 It is clear that every asymptotically
pseudocon-tractive mapping (with𝑃) is asymptotically pseudocontrac-tive type (with𝑃) and every asymptotically pseudocontrac-tive type (with𝑃) is asymptotically quasi pseudocontractive type (with𝑃) If 𝑇 : 𝐶 → 𝐶 is a self-mapping, then we can choose 𝑃 = 𝐼 as the identical mapping and we can get the usual definition of asymptotically pseudocontractive mapping, and so forth
Definition 3 Let 𝐶 be a nonexpansive retract (with 𝑃) of
𝐸, let 𝑇1, 𝑇2 : 𝐶 → 𝐸 be two uniformly L-Lipschitzian non-self-mappings and let 𝑇1 be an asymptotically quasi pseudocontractive type (with𝑃)
The sequence {𝑥𝑛} is called the new modified mixed Ishikawa iterative sequence with error (with 𝑃), if {𝑥𝑛} is generated by
𝑥𝑛+1= 𝑃 ((1 − 𝛼𝑛− 𝛾𝑛) 𝑥𝑛+ 𝛼𝑛𝑇1(𝑃𝑇1)𝑛−1
× ((1 − 𝛽𝑛) 𝑦𝑛+ 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛) + 𝛾𝑛𝑢𝑛) ,
𝑦𝑛= 𝑃 ((1 − 𝛼𝑛− 𝛾𝑛) 𝑥𝑛+ 𝛼𝑛𝑇2(𝑃𝑇2)𝑛−1
× ((1 − 𝛽𝑛) 𝑥𝑛+ 𝛽𝑛𝑇2(𝑃𝑇2)𝑛−1𝑥𝑛) + 𝛾𝑛V𝑛) ,
(12)
where𝑥1∈ 𝐶 is arbitrary, {𝑢𝑛} and {V𝑛} ⊂ 𝐶 are bounded, and
𝛼𝑛, 𝛽𝑛, 𝛾𝑛, 𝛼
𝑛, 𝛽
𝑛, 𝛾
𝑛∈ [0, 1], 𝑛 = 1, 2,
If𝛼
𝑛= 𝛽
𝑛= 𝛾
𝑛 = 0, (12) turns to
𝑥𝑛+1= 𝑃 ((1 − 𝛼𝑛− 𝛾𝑛) 𝑥𝑛+ 𝛼𝑛𝑇1(𝑃𝑇1)𝑛−1
× ((1 − 𝛽𝑛) 𝑥𝑛+ 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛) + 𝛾𝑛𝑢𝑛) , (13) and it is called the new modified mixed Mann iterative sequence with error (with𝑃)
If𝛾𝑛= 𝛾
𝑛= 0, (12) becomes
𝑥𝑛+1= 𝑃 ( (1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇1(𝑃𝑇1)𝑛−1
× ((1 − 𝛽𝑛) 𝑦𝑛+ 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛)) ,
𝑦𝑛= 𝑃 ( (1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇2(𝑃𝑇2)𝑛−1
× ((1 − 𝛽𝑛) 𝑥𝑛+ 𝛽𝑛𝑇2(𝑃𝑇2)𝑛−1𝑥𝑛)) ,
(14)
and it is called the new modified mixed Ishikawa iterative sequence (with𝑃)
If𝛽𝑛 = 𝛽
𝑛= 0, (14) turns to
𝑥𝑛+1= 𝑃 ((1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛) ,
𝑦𝑛= 𝑃 ((1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇2(𝑃𝑇2)𝑛−1𝑥𝑛) , (15) and it is called the new mixed Ishikawa iterative sequence (with𝑃)
If𝑇1 = 𝑇2 = 𝑇 : 𝐶 → 𝐶 is a self-mapping and 𝑃 = 𝐼 is the identical mapping, then (15) is just the modified Ishikawa iterative sequence
𝑥𝑛+1= (1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇𝑛𝑦𝑛,
𝑦𝑛= (1 − 𝛼𝑛) 𝑥𝑛+ 𝛼𝑛𝑇𝑛𝑥𝑛 (16)
Trang 3𝑛 = 0, (15) becomes (6), obviously So, iterative method
(12) is greatly generalized
The following lemmas will be needed in what follows to
prove our main results
Lemma 4 (see [19]) Let 𝐸 be a real Banach space Then, for
all 𝑥, 𝑦 ∈ 𝐸, 𝑗(𝑥+𝑦) ∈ 𝐽(𝑥+𝑦), the following inequality holds:
𝑥 + 𝑦2≤ ‖𝑥‖2+ 2 ⟨𝑥, 𝑗 (𝑥 + 𝑦)⟩ (17)
Lemma 5 (see [6,7]) Let{𝑎𝑛}, {𝑏𝑛}, {𝑐𝑛} be three sequences of
nonnegative numbers satisfying the recursive inequality:
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛+ 𝑐𝑛, ∀𝑛 ≥ 𝑛0, (18)
where𝑛0is some nonnegative integer IfΣ∞
𝑛=1𝑏𝑛< ∞, Σ∞
𝑛=1𝑐𝑛<
∞, then lim𝑛 → ∞𝑎𝑛exists.
Lemma 6 Suppose that 𝜙 : [0, +∞) → [0, +∞) is a strictly
increasing function with 𝜙(0) = 0 Let {𝑎𝑛}, {𝑏𝑛}, {𝑐𝑛}, {𝜆𝑛} (0 ≤
𝜆𝑛 ≤ 1) be four sequences of nonnegative numbers satisfying
the recursive inequality:
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝜆𝑛𝜙 (𝑎𝑛+1) + 𝑐𝑛, ∀𝑛 ≥ 𝑛0, (19)
where𝑛0is some nonnegative integer IfΣ∞
𝑛=1𝑏𝑛< ∞, Σ∞
𝑛=1𝑐𝑛<
∞, Σ∞
𝑛=1𝜆𝑛= ∞, then lim𝑛 → ∞𝑎𝑛= 0.
Proof From (19), we get
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛+ 𝑐𝑛, ∀𝑛 ≥ 𝑛0 (20)
By Lemma5, we know that lim𝑛 → ∞𝑎𝑛 = 𝑎 ≥ 0 exists Let
𝑀 = sup1≤𝑛≤∞{𝑎𝑛} < ∞ Now we show 𝑎 = 0 Otherwise, if
𝑎 > 0, then ∃𝑛1 ≥ 𝑛0, such that𝑎𝑛+1≥ (1/2)𝑎 > 0 when 𝑛 ≥
𝑛1 Because𝜙 is a strictly increasing function, so 𝜙(𝑎𝑛+1) ≥
𝜙((1/2)𝑎) > 0 From (19) again, we have
0 < 𝜙 (1
2𝑎)
∞
∑
𝑛=1
𝜆𝑛
= 𝜙 (1
2𝑎)
𝑛 1
∑
𝑛=1
𝜆𝑛+ 𝜙 (1
2𝑎)
∞
∑
𝑛=𝑛 1 +1
𝜆𝑛
≤ 𝜙 (12𝑎)∑𝑛1
𝑛=1𝜆𝑛+ ∑∞
𝑛=𝑛1+1𝜆𝑛𝜙 (𝑎𝑛+1)
≤ 𝜙 (12𝑎)∑𝑛1
𝑛=1
𝜆𝑛+ ∑∞
𝑛=𝑛 1 +1
(𝑎𝑛− 𝑎𝑛+1)
+ ∑∞
𝑛=𝑛 1 +1
𝑏𝑛𝑎𝑛+ ∑∞
𝑛=𝑛 1 +1
𝑐𝑛
≤ 𝜙 (1
2𝑎)
𝑛 1
∑
𝑛=1
𝜆𝑛+ 𝑎𝑛1+1+ 𝑀∑∞
𝑛=1
𝑏𝑛+∑∞
𝑛=1
𝑐𝑛< ∞
(21)
This is a contradiction with the given conditionΣ∞𝑛=1𝜆𝑛= ∞
Therefore lim𝑛 → ∞𝑎𝑛 = 0
Lemma 7 Suppose that 𝜙 : [0, +∞) → [0, +∞) is a strictly
increasing function with 𝜙(0) = 0 Let {𝑎𝑛}, {𝑏𝑛}, {𝑐𝑛}, {𝜆𝑛} (0 ≤
𝜆𝑛≤ 1), {𝜀𝑛} be five sequences of nonnegative numbers satisfy-ing the recursive inequality:
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝜆𝑛𝜙 (𝑎𝑛+1) + 𝑐𝑛+ 𝜆𝑛𝜀𝑛, ∀𝑛 ≥ 𝑛0,
(22)
where𝑛0is some nonnegative integer IfΣ∞𝑛=1𝑏𝑛< ∞, Σ∞𝑛=1𝑐𝑛<
∞, Σ∞𝑛=1𝜆𝑛= ∞, lim𝑛 → ∞𝜀𝑛= 0, then lim𝑛 → ∞𝑎𝑛= 0 Proof Firstly, we show lim inf𝑛 → ∞𝑎𝑛= 𝑎 = 0 If 𝑎 > 0, then, for arbitrary𝑟 ∈ (0, 𝑎), ∃𝑛1 ≥ 𝑛0, such that𝑎𝑛+1 ≥ 𝑟 > 0 when𝑛 ≥ 𝑛1 Because𝜙 is a strictly increasing function and lim𝑛 → ∞𝜀𝑛 = 0, so 𝜙(𝑎𝑛+1) ≥ 𝜙(𝑟) > 0 and 𝜀𝑛 ≤ (1/2)𝜙(𝑟) when𝑛 ≥ 𝑛1 From (22), we have
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝜆𝑛𝜙 (𝑎𝑛+1) + 𝑐𝑛+ 𝜆𝑛1
2𝜙 (𝑎𝑛+1)
= (1 + 𝑏𝑛) 𝑎𝑛−1
2𝜆𝑛𝜙 (𝑎𝑛+1) + 𝑐𝑛, ∀𝑛 ≥ 𝑛1.
(23)
By Lemma6, we get0 = lim𝑛 → ∞𝑎𝑛 = lim inf𝑛 → ∞𝑎𝑛= 𝑎 > 0 This is contradictory So, lim inf𝑛 → ∞𝑎𝑛 = 0
Secondly,∀𝜀 > 0, from the given conditions in Lemma7,
∃𝑛2≥ 𝑛0, when∀𝑛 ≥ 𝑛2, we have
𝜀𝑛≤ 𝜙 (𝜀) , ∑∞
𝑛=𝑛 2
𝑏𝑛≤ ln 2, ∑∞
𝑛=𝑛 2
𝑐𝑛≤ 𝜀 (24)
On the other hand, since lim inf𝑛 → ∞𝑎𝑛 = 0, ∃𝑁 ≥ 𝑛2 such that𝑎𝑁≤ 𝜀 Now we claim
𝑎𝑘≤ (𝜀 + 𝑘−1∑
𝑛=𝑁
𝑐𝑛) exp (𝑘−1∑
𝑛=𝑁
𝑏𝑛) , ∀𝑘 ≥ 𝑁 (25)
In fact, when𝑘 = 𝑁, (25) holds Suppose that (25) holds for
𝑘 dose not for 𝑘 + 1 Then
𝑎𝑘+1> (𝜀 + ∑𝑘
𝑛=𝑁
𝑐𝑛) exp (∑𝑘
𝑛=𝑁
𝑏𝑛) (26)
Furthermore,𝑎𝑘+1> 𝜀, 𝜙(𝑎𝑘+1) > 𝜙(𝜀) But by (22), (24), and the inductive hypothesis, we have
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝜆𝑛𝜙 (𝑎𝑛+1) + 𝑐𝑛+ 𝜆𝑛𝜀𝑛
≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝜆𝑛𝜙 (𝜀) + 𝑐𝑛+ 𝜆𝑛𝜙 (𝜀)
≤ (1 + 𝑏𝑛) (𝜀 +𝑘−1∑
𝑛=𝑁
𝑐𝑛) exp (𝑘−1∑
𝑛=𝑁
𝑏𝑛) + 𝑐𝑛
≤ (𝜀 + 𝑘−1∑
𝑛=𝑁
𝑐𝑛) exp (∑𝑘
𝑛=𝑁
𝑏𝑛) + 𝑐𝑛
≤ (𝜀 + ∑𝑘
𝑛=𝑁
𝑐𝑛) exp (∑𝑘
𝑛=𝑁
𝑏𝑛)
(27)
Trang 4This is a contradiction with (26) So, (25) holds Whereupon,
lim sup
𝑘 → ∞ 𝑎𝑘≤ (𝜀 + ∑∞
𝑛=𝑁
𝑐𝑛) exp (∑∞
𝑛=𝑁
𝑏𝑛)
≤ 2 (𝜀 + 𝜀) = 4𝜀
(28)
Therefore, lim sup𝑘 → ∞𝑎𝑘= 0 = lim𝑛 → ∞𝑎𝑛
3 Main Results
Now, we are in a position to state and prove the main results
of this paper
Theorem 8 Let 𝐶 be nonexpansive retract (with 𝑃) of a
real Banach space 𝐸 Assume that 𝑇1, 𝑇2 : 𝐶 → 𝐸 are
two uniformly L-Lipschitzian non-self-mappings (with 𝑃) and
𝑇1 is an asymptotically quasi pseudocontractive type with
coefficient numbers {𝑘𝑛} ⊂ [1, +∞) : 𝑘𝑛 → 1 satisfying
𝐹 = 𝐹(𝑇1) ∩ 𝐹(𝑇2) ̸= 0 Suppose that {𝑢𝑛}, {V𝑛} ⊂ 𝐶 are two
bounded sequences;{𝛼𝑛}, {𝛽𝑛}, {𝛾𝑛}, {𝛼𝑛}, {𝛽𝑛}, {𝛾𝑛} ⊂ [0, 1] are
six number sequences satisfying the following:
(C1)Σ∞
𝑛=1𝛼𝑛 = +∞, Σ∞
𝑛=1𝛼2
𝑛 < +∞, Σ∞
𝑛=1𝛼𝑛(𝑘𝑛− 1) < +∞;
(C2)𝛼𝑛+ 𝛾𝑛≤ 1, 𝛼
𝑛+ 𝛾
𝑛 ≤ 1, Σ∞ 𝑛=1𝛾𝑛< +∞;
(C3)Σ∞
𝑛=1𝛼𝑛𝛽𝑛< +∞, Σ∞
𝑛=1𝛼𝑛𝛼
𝑛< +∞, Σ∞
𝑛=1𝛼𝑛𝛾
𝑛< +∞
If𝑥1∈ 𝐶 is arbitrary, then the iterative sequence {𝑥𝑛} generated
by (12) converges strongly to the fixed point𝑥∗ ∈ 𝐹 if and only
if there exists a strictly increasing function𝜙 : [0, +∞) →
[0, +∞) with 𝜙(0) = 0 such that
lim sup
𝑗(𝑥 𝑛+1 −𝑥 ∗)∈𝐽(𝑥 𝑛+1 −𝑥 ∗)[⟨𝑇1(𝑃𝑇1)
𝑛−1𝑥𝑛+1− 𝑥∗,
𝑗 (𝑥𝑛+1− 𝑥∗) ⟩− 𝑘𝑛𝑥𝑛+1− 𝑥∗2
+ 𝜙 (𝑥𝑛+1− 𝑥∗)] ≤ 0
(29)
Proof (Adequacy) Let
𝜀𝑛= inf
𝑗(𝑥 𝑛+1 −𝑥 ∗)∈𝐽(𝑥 𝑛+1 −𝑥 ∗)[⟨𝑇1(𝑃𝑇1)
𝑛−1𝑥𝑛+1− 𝑥∗,
𝑗 (𝑥𝑛+1− 𝑥∗) ⟩ − 𝑘𝑛𝑥𝑛+1− 𝑥∗2
+ 𝜙 (𝑥𝑛+1− 𝑥∗)],
𝜀𝑛 = max {𝜀𝑛, 0} +1𝑛
(30) Then there exists𝑗(𝑥𝑛+1− 𝑥∗) ∈ 𝐽(𝑥𝑛+1− 𝑥∗) such that
⟨𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
− 𝑘𝑛𝑥𝑛+1− 𝑥∗2
+ 𝜙 (𝑥𝑛+1− 𝑥∗) ≤ 𝜀𝑛 (31)
From (29), we know that lim sup𝑛 → ∞𝜀
𝑛 ≤ 0 So, lim𝑛 → ∞𝜀𝑛= 0
Now, from the given conditions and (12), we can let
𝜎𝑛= (1 − 𝛽𝑛) 𝑦𝑛+ 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛,
𝛿𝑛= (1 − 𝛽𝑛) 𝑥𝑛+ 𝛽𝑛𝑇2(𝑃𝑇2)𝑛−1𝑥𝑛, (32) and𝑀 = sup𝑛≥1{‖𝜇𝑛− 𝑥∗‖, ‖]𝑛− 𝑥∗‖} < ∞ Then
𝛿𝑛− 𝑥∗ ≤ 𝛽
𝑛𝑇2(𝑃𝑇2) 𝑥𝑛− 𝑥∗ + (1 − 𝛽
𝑛) 𝑥𝑛− 𝑥∗
≤ 𝛽𝑛𝐿 𝑥𝑛− 𝑥∗ + 𝑥𝑛− 𝑥∗;
𝑦𝑛− 𝑥∗ ≤ (1 − 𝛼
𝑛− 𝛾𝑛) 𝑥𝑛− 𝑥∗
+ 𝛼𝑛𝐿 𝛿𝑛− 𝑥∗ + 𝛾
𝑛]𝑛− 𝑥∗
≤ 𝑥𝑛− 𝑥∗ + 𝛼
𝑛𝛽
𝑛𝐿2𝑥𝑛− 𝑥∗
+ 𝛼𝑛𝐿 𝑥𝑛− 𝑥∗ + 𝛾
𝑛𝑀
= (1 + 𝛼
𝑛𝛽
𝑛𝐿2+ 𝛼
𝑛𝐿) 𝑥𝑛− 𝑥∗ + 𝛾
𝑛𝑀
≤ (1 + 𝐿 + 𝐿2) 𝑥𝑛− 𝑥∗ + 𝑀;
𝜎𝑛− 𝑥∗ ≤ 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛− 𝑥∗
+ (1 − 𝛽𝑛) 𝑦𝑛− 𝑥∗
≤ 𝛽𝑛𝐿 𝑦𝑛− 𝑥∗ + 𝑦𝑛− 𝑥∗
≤ (1 + 𝐿) (1 + 𝐿 + 𝐿2) 𝑥𝑛− 𝑥∗ + (1 + 𝐿)𝑀;
𝑦𝑛− 𝑥𝑛+1 ≤ 𝛼𝑛𝐿 𝜎𝑛− 𝑥∗ + 𝛼𝑛𝑥𝑛− 𝑥∗
+ 𝛼𝑛𝐿 𝛿𝑛− 𝑥∗ + 𝛼
𝑛𝑥𝑛− 𝑥∗
+ (𝛾𝑛+ 𝛾𝑛) 𝑥𝑛− 𝑥∗ + (𝛾𝑛+ 𝛾𝑛) 𝑀
≤ 𝛼𝑛𝐿 [(1 + 𝐿) (1 + 𝐿 + 𝐿2) 𝑥𝑛− 𝑥∗
+ (1 + 𝐿) 𝑀]
+ 𝛼𝑛𝐿 [(1 + 𝛽𝑛𝐿) 𝑥𝑛− 𝑥∗]
+ (𝛼𝑛+ 𝛼𝑛+ 𝛾𝑛+ 𝛾𝑛) 𝑥𝑛− 𝑥∗ + (𝛾𝑛+ 𝛾𝑛) 𝑀
≤ [𝛼𝑛𝐿 (1 + 𝐿) (1 + 𝐿 + 𝐿2) + 𝛼𝑛𝐿 (1 + 𝛽𝑛𝐿) + 𝛼𝑛+ 𝛼
𝑛+ 𝛾𝑛+ 𝛾
𝑛] 𝑥𝑛− 𝑥∗
+ (𝛼𝑛𝐿 (1 + 𝐿) + 𝛾𝑛+ 𝛾𝑛)𝑀;
𝜎𝑛− 𝑥𝑛+1 ≤ 𝑦𝑛− 𝑥𝑛+1 + 𝛽𝑛𝑇1(𝑃𝑇1)𝑛−1𝑦𝑛− 𝑦𝑛
≤ 𝑠𝑛𝑥𝑛− 𝑥∗ + 𝑡𝑛,
(33)
Trang 5𝑠𝑛= 𝛼𝑛𝐿 (1 + 𝐿) (1 + 𝐿 + 𝐿2) + 𝛼𝑛𝐿 (1 + 𝛽𝑛𝐿)+ 𝛼𝑛
+ 𝛼𝑛+ 𝛾𝑛+ 𝛾𝑛+ 𝛽𝑛(1 + 𝐿) (1 + 𝐿 + 𝐿2) ;
𝑡𝑛 = [𝛼𝑛𝐿 (1 + 𝐿) + 𝛾𝑛+ 𝛾𝑛+ 𝛽𝑛(1 + 𝐿)] 𝑀
(34)
So, by Lemma4,
2𝛼𝑛⟨𝑇1(𝑃𝑇1)𝑛−1𝜎𝑛− 𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
≤ 2𝛼𝑛𝐿 𝑥𝑛+1− 𝑥∗𝜎𝑛− 𝑥𝑛+1
≤ 2𝛼𝑛𝐿 𝑥𝑛+1− 𝑥∗[𝑠𝑛𝑥𝑛− 𝑥∗ + 𝑡𝑛] ;
(35)
𝑥𝑛+1− 𝑥∗2
≤ (1 − 𝛼𝑛− 𝛾𝑛)2𝑥𝑛− 𝑥∗2
+ 2𝛼𝑛⟨𝑇1(𝑃𝑇1)𝑛−1𝜎𝑛− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
+ 2𝛾𝑛⟨𝜇𝑛− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
≤ (1 − 𝛼𝑛− 𝛾𝑛)2𝑥𝑛− 𝑥∗2
+ 2𝛼𝑛⟨𝑇1(𝑃𝑇1)𝑛−1𝜎𝑛− 𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1,
𝑗 (𝑥𝑛+1− 𝑥∗) ⟩
+ 2𝛼𝑛⟨𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
+ 2𝛾𝑛𝑀 𝑥𝑛+1− 𝑥∗
(36)
For the third in (36), we have
2𝛼𝑛⟨𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
= 2𝛼𝑛𝑑𝑛+ 2𝛼𝑛[𝑘𝑛𝑥𝑛+1− 𝑥∗2
− 𝜙 (𝑥𝑛+1− 𝑥∗)]
≤ 2𝛼𝑛𝜀𝑛+ 2𝛼𝑛[𝑘𝑛𝑥𝑛+1− 𝑥∗2
− 𝜙 (𝑥𝑛+1− 𝑥∗)],
(37)
where
𝑑𝑛= ⟨𝑇1(𝑃𝑇1)𝑛−1𝑥𝑛+1− 𝑥∗, 𝑗 (𝑥𝑛+1− 𝑥∗)⟩
− 𝑘𝑛𝑥𝑛+1− 𝑥∗2
+ 𝜙 (𝑥𝑛+1− 𝑥∗) ≤ 𝜀𝑛 (38) Substituting (35) into (36), we get
𝑥𝑛+1− 𝑥∗2≤ (1 − 𝛼𝑛)2𝑥𝑛− 𝑥∗2+ 2𝛼𝑛𝜀𝑛
+ 2𝛼𝑛𝑘𝑛𝑥𝑛+1− 𝑥∗2− 2𝛼𝑛𝜙 (𝑥𝑛+1− 𝑥∗) + 2𝛼𝑛𝐿 (𝑠𝑛𝑥𝑛− 𝑥∗ + 𝑡𝑛) 𝑥𝑛+1− 𝑥∗
+ 2𝛾𝑛𝑀 𝑥𝑛+1− 𝑥∗
(39)
Let𝑎𝑛 = ‖𝑥𝑛− 𝑥∗‖2,𝜑(𝑡) = 2𝜙(√𝑡), and
𝜉𝑛 = 𝐿𝛼𝑛𝑠𝑛
= 𝐿2𝛼2
𝑛(1 + 𝐿) (1 + 𝐿 + 𝐿2) + 𝛼𝑛𝛼𝑛𝐿2(1 + 𝛽𝑛𝐿)+ 𝛼2𝑛𝐿 + 𝛼𝑛𝛼𝑛𝐿 + 𝐿𝛼𝑛𝛾𝑛 + 𝐿𝛼𝑛𝛾𝑛+ 𝐿𝛼𝑛𝛽𝑛(1 + 𝐿) (1 + 𝐿 + 𝐿2) ,
(40)
𝜌𝑛 = 𝐿𝛼𝑛𝑡𝑛+ 𝑀𝛾𝑛
= [𝛼2𝑛𝐿2(1 + 𝐿) + 𝐿𝛼𝑛𝛾𝑛+ 𝐿𝛼𝑛𝛾𝑛+ 𝛼𝑛𝛽𝑛(𝐿 + 𝐿2) ] 𝑀 + 𝛾𝑛𝑀
(41) Then (39) becomes
𝑎𝑛+1≤ (1 − 𝛼𝑛)2𝑎𝑛+ 2𝛼𝑛𝜀𝑛+ 2𝛼𝑛𝑘𝑛𝑎𝑛+1− 𝛼𝑛𝜑 (𝑎𝑛+1) + 2 (𝜉𝑛𝑥𝑛− 𝑥∗ + 𝜌𝑛) 𝑥𝑛+1− 𝑥∗ (42)
By using2𝑎𝑏 ≤ 𝑎2+ 𝑏2, we have
𝑎𝑛+1≤ (1 − 𝛼𝑛)2𝑎𝑛+ 2𝛼𝑛𝜀𝑛+ 2𝛼𝑛𝑘𝑛𝑎𝑛+1
− 𝛼𝑛𝜑 (𝑎𝑛+1) + 𝜉𝑛(𝑎𝑛+ 𝑎𝑛+1) + 𝜌𝑛(1 + 𝑎𝑛+1)
= (1 − 2𝛼𝑛+ 𝛼2𝑛+ 𝜉𝑛) 𝑎𝑛+ (2𝛼𝑛𝑘𝑛+ 𝜉𝑛+ 𝜌𝑛) 𝑎𝑛+1
− 𝛼𝑛𝜑 (𝑎𝑛+1) + 2𝛼𝑛𝜀𝑛+ 𝜌𝑛
(43)
From (40), (41), and the given conditions, we know
∞
∑
𝑛=1
𝛼2𝑛< +∞, ∑∞
𝑛=1
𝜉𝑛 < +∞, ∑∞
𝑛=1
𝜌𝑛 < +∞ (44)
Then, lim𝑛 → ∞(2𝛼𝑛𝑘𝑛 + 𝜉𝑛 + 𝜌𝑛) = 0 Therefore ∃𝑛0, when
𝑛 ≥ 𝑛0,2𝛼𝑛𝑘𝑛+ 𝜉𝑛+ 𝜌𝑛≤ 1/2 Let
𝑏𝑛 = 1 − 2𝛼1 − 2𝛼𝑛+ 𝛼2𝑛+ 𝜉𝑛
𝑛𝑘𝑛− 𝜉𝑛− 𝜌𝑛 − 1 =
2𝛼𝑛(𝑘𝑛− 1) + 𝛼𝑛2+ 2𝜉𝑛+ 𝜌𝑛
1 − 2𝛼𝑛𝑘𝑛− 𝜉𝑛− 𝜌𝑛 ;
𝑐𝑛 = 1 − 2𝛼 𝜌𝑛
𝑛𝑘𝑛− 𝜉𝑛− 𝜌𝑛.
(45)
So, when𝑛 ≥ 𝑛0, we get
0 ≤ 𝑏𝑛≤ 2 [2𝛼𝑛(𝑘𝑛− 1) + 𝛼2𝑛+ 2𝜉𝑛+ 𝜌𝑛] , 0 ≤ 𝑐𝑛≤ 2𝜌𝑛
(46) From (44) and the given conditions, we have∑∞𝑛=𝑛0𝑏𝑛 < +∞,
∑∞𝑛=𝑛0𝑐𝑛< +∞ On the other hand, from (43), we have
𝑎𝑛+1≤ (1 + 𝑏𝑛) 𝑎𝑛− 𝛼𝑛𝜑 (𝑎𝑛+1) + 4𝛼𝑛𝜀𝑛+ 𝑐𝑛, ∀𝑛 ≥ 𝑛0
(47)
Trang 6By Lemma7, we at last get
lim
𝑛 → ∞𝑎𝑛 = lim𝑛 → ∞𝑥𝑛− 𝑥∗2= 0; (48)
for example, lim𝑛 → ∞𝑥𝑛= 𝑥∗∈ 𝐹 = 𝐹(𝑇1) ∩ 𝐹(𝑇2)
(Necessity) Suppose that lim𝑛 → ∞𝑥𝑛 = 𝑥∗ ∈ 𝐹 Then we can
choose an arbitrary continuous strictly increasing function
𝜙 : [0, +∞) → [0, +∞) with 𝜙(0) = 0, such as 𝜙(𝑡) = 𝑡
We can get lim𝑛 → ∞𝜙(‖𝑥𝑛+1− 𝑥∗‖) = 0
Because𝑇1is an asymptotically quasi pseudocontractive
type (with𝑃), by (11) in Definition1, for any𝑝 ∈ 𝐹(𝑇1) ⊇ 𝐹,
we have
lim sup
𝑛 → ∞ sup
𝑥∈𝐶 lim inf
𝑗(𝑥−𝑝)∈𝐽(𝑥−𝑝)(⟨𝑇(𝑃𝑇)𝑛−1𝑥 − 𝑝, 𝑗 (𝑥 − 𝑦)⟩
− 𝑘𝑛𝑥 − 𝑝2) ≤ 0
(49)
So,
lim sup
𝑛 → ∞ inf
𝑗(𝑥𝑛+1−𝑥 ∗)∈𝐽(𝑥𝑛+1−𝑥 ∗)[⟨𝑇1(𝑃𝑇1)
𝑛−1𝑥𝑛+1− 𝑥∗,
𝑗 (𝑥𝑛+1− 𝑥∗) ⟩− 𝑘𝑛𝑥𝑛+1− 𝑥∗2
+ 𝜙 (𝑥𝑛+1− 𝑥∗)]
= lim sup
𝑛 → ∞ inf
𝑗(𝑥𝑛+1−𝑥 ∗)∈𝐽(𝑥𝑛+1−𝑥 ∗)[⟨𝑇1(𝑃𝑇1)
𝑛−1𝑥𝑛+1− 𝑥∗,
𝑗 (𝑥𝑛+1− 𝑥∗) ⟩
− 𝑘𝑛𝑥𝑛+1− 𝑥∗2] + lim𝑛 → ∞𝜙 (𝑥𝑛+1− 𝑥∗) ≤ 0 + 0 = 0;
(50) that is, (29) holds This completes the proof of Theorem8
Combining with Theorem8 and Definition3, we have
some results as follows
Theorem 9 Let 𝐶 be nonexpansive retract (with 𝑃) of a real
Banach space 𝐸 Assume that 𝑇1, 𝑇2 : 𝐶 → 𝐸 are two
uniformly L-Lipschitzian non-self-mappings (with 𝑃) and 𝑇1is
an asymptotically quasi pseudocontractive type with coefficient
numbers{𝑘𝑛} ⊂ [1, +∞) : 𝑘𝑛 → 1 satisfying 𝐹 = 𝐹(𝑇1) ∩
𝐹(𝑇2) ̸= 0 Suppose that {𝛼𝑛}, {𝛽𝑛}, {𝛼
𝑛}, {𝛽
𝑛} ⊂ [0, 1] are four number sequences satisfying the following:
(C1)Σ∞
𝑛=1𝛼𝑛 = +∞, Σ∞
𝑛=1𝛼2
𝑛 < +∞, Σ∞
𝑛=1𝛼𝑛(𝑘𝑛− 1) < +∞;
(C2)Σ∞
𝑛=1𝛼𝑛𝛽𝑛< +∞, Σ∞
𝑛=1𝛼𝑛𝛼
𝑛< +∞.
If𝑥1∈ 𝐶 is arbitrary, then the iterative sequence {𝑥𝑛} generated
by (14) converges strongly to the fixed point𝑥∗ ∈ 𝐹 if and only
if there exists a strictly increasing function𝜙 : [0, +∞) →
[0, +∞) with 𝜙(0) = 0 such that (29) holds.
Theorem 10 Let 𝐶 be nonexpansive retract (with 𝑃) of a real
Banach space 𝐸 Assume that 𝑇1, 𝑇2 : 𝐶 → 𝐸 are two
uniformly L-Lipschitzian non-self-mappings (with 𝑃) and 𝑇1is
an asymptotically quasi pseudocontractive type with coefficient numbers{𝑘𝑛} ⊂ [1, +∞) : 𝑘𝑛 → 1 satisfying 𝐹 = 𝐹(𝑇1) ∩ 𝐹(𝑇2) ̸= 0 Suppose that {𝛼𝑛}, {𝛼
𝑛} ⊂ [0, 1] are two number sequences satisfying the following:
(C1)Σ∞ 𝑛=1𝛼𝑛 = +∞, Σ∞
𝑛=1𝛼2
𝑛 < +∞, Σ∞
𝑛=1𝛼𝑛(𝑘𝑛− 1) < +∞;
(C2)Σ∞ 𝑛=1𝛼𝑛𝛼
𝑛< +∞.
If𝑥1∈ 𝐶 is arbitrary, then the iterative sequence {𝑥𝑛} generated
by (15) converges strongly to the fixed point𝑥∗ ∈ 𝐹 if and only
if there exists a strictly increasing function𝜙 : [0, +∞) →
[0, +∞) with 𝜙(0) = 0 such that (29) holds.
Theorem 11 Let 𝐶 be a nonempty closed convex subset of a
real Banach space 𝐸 Assume that 𝑇 : 𝐶 → 𝐶 is uniformly L-Lipschitzian self-mappings and asymptotically quasi pseudo-contractive type with coefficient numbers{𝑘𝑛} ⊂ [1, +∞) :
𝑘𝑛 → 1 satisfying 𝐹 = 𝐹(𝑇) ̸= 0 Suppose that {𝛼𝑛}, {𝛼
𝑛} ⊂
[0, 1] are two number sequences satisfying the following:
(C1)Σ∞ 𝑛=1𝛼𝑛 = +∞, Σ∞
𝑛=1𝛼2
𝑛 < +∞, Σ∞
𝑛=1𝛼𝑛(𝑘𝑛− 1) < +∞;
(C2)Σ∞ 𝑛=1𝛼𝑛𝛼
𝑛< +∞.
If𝑥1∈ 𝐶 is arbitrary, then the iterative sequence {𝑥𝑛} generated
by (16) converges strongly to the fixed point𝑥∗∈ 𝐹 if and only
if there exists a strictly increasing function𝜙 : [0, +∞) →
[0, +∞) with 𝜙(0) = 0 such that (29) holds.
Remark 12 Our research and results in this paper have the
following several advantaged characteristics (a) The iterative scheme is the new modified mixed Ishikawa iterative scheme with error on two mappings𝑇1, 𝑇2 (b) The common fixed point 𝑥∗ ∈ 𝐹 = 𝐹(𝑇1) ∩ 𝐹(𝑇2) is studied (c) The research object is the very generalized asymptotically quasi pseudocontractive type (with𝑃) non-self-mapping (d) The tool used by us is the very powerful tool: Lemma 7 So, our results here extend and improve many results of other authors to a certain extent, such as [6,8,14–23], and the proof methods are very different from the previous
Conflict of Interests
The authors declare that there is no conflict of interests regarding the publication of this paper
Acknowledgments
The authors would like to thank the editors and referees for their many useful comments and suggestions for the improvement of the paper This work was supported by the National Natural Science Foundations of China (Grant no 11271330) and the Natural Science Foundations of Zhejiang Province (Grant no Y6100696)
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