Consider a stock with a virtual price process that follows a continuous geometricBrownian motion, with a net expected annual return and standard deviation of returnnot continuously compo
Trang 1The Econometrics of Financial Markets
Petr Adamek John Y Campbell Andrew W Lo
A Craig MacKinlay Luis M ViceiraAuthor address:
MIT Sloan School, 50 Memorial Drive, Cambridge, MA 02142{1347 Department of Economics, Harvard University, Littauer Center, Cam- bridge, MA 02138
MIT Sloan School, 50 Memorial Drive, Cambridge, MA 02142{1347 Wharton School, University of Pennsylvania, 3620 Locust Walk, Philadel- phia, PA 19104{6367
Department of Economics, Harvard University, Littauer Center, bridge, MA 02138
Trang 5List of Figures
3.3 Histogram of IBM Price Changes Falling on Odd or Even Eighth 15
12.1 Kernel Regression of IBM Returns on S&P 500 Returns 63
Trang 7List of Tables
2.3 Statistics for Daily and Monthly Simple and Continuously Compounded
3.4 Unconditional and Conditional Distributions of Bid/Ask Spreads 20
Trang 9PrefaceThe problems inThe Econometrics of Financial Marketshave been tested in PhD courses
at Harvard, MIT, Princeton, and Wharton over a number of years We are grateful to thestudents in these courses who served as guinea pigs for early versions of these problems,and to our teaching assistants who helped to prepare versions of the solutions We alsothank Leonid Kogan for assistance with some of the more challenging problems in Chapter9
Trang 11Problems in Chapter 2
Solution 2.1 2.1.1Recall the martingale property given by (2.1.2) and observe that the mean-squarederror of the time-tforecastXt of pricePt +1is
(S2.1.2)
= E[0(Pt ; k ; l ;Pt ;2 k ; l)] = 0:
Solution 2.2Denote the martingale property (2.1.2) by M Then
nand2 n jn j ;1=2 satis es RW3 but not M; (ii)n nn ;1 satis es Mbut not RW2; (iii)n nnsatis es RW2 but not RW1
Solution 2.3
A necessary condition for the log-price processptin (2.2.9) to satisfy RW1 is+ = 1 Let
c+ and consider the set of all non-RW1 Markov processes (2.2.9), i.e.,c6= 1 Therestriction CJ = 1 is equivalent to =c=4 The constraints 0; 1 are satis edexactly forc2[1;4=3] and therefore the set of all two-state Markov chains represented bythe pair (; ) that cannot support any RW1 process but still yields CJ = 1 is simply
f(1 p
Var[Zt(q)] = q;1
X
k =0Var[Zt ; k] + 2q;1
X
k =1(q;k)Cov[Zt;Zt ; k](S2.4.1)
which yields (2.4.19) The coecients of Cov[Zt;Zt ; k] are simply the number of k-thorder autocovariance terms in the variance of the multiperiod returnZt(q) (recall that thismultiperiod return is the sum ofq one-period returns) The coecients decline linearly
Trang 12Ten individual stocksused for problem 2.5, identi rstNassets and the market portfolio,
2 4
(S5.4.4)
2 4
0;1
1
2 m +
0;1
(S5.4.6)
;1 :
(S5.4.9)
From (S5.4.2) and (S5.4.9) we have
0;1 =2
... expected annual returns dened as rescaledarithmeticaverage ofdailyreturns, and the estimator ^ of the volatility of annual returns
dened as a rescaled standard deviation ofdaily... of discretization of prices to< /p>
a $1/8 grid on naive estimates of annual mean and standard deviation based on dailyreturns data is simulated for a hypothetical stock following a continuous... changes to volume, according to the Gauss-Markov theorem
Trang 27Histogram of IBM’s Bid/Ask