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Tiêu đề Cover Times for Brownian Motion and Random Walks in Two Dimensions
Tác giả Amir Dembo, Yuval Peres, Jay Rosen, Ofer Zeitouni
Trường học University of Mathematics
Chuyên ngành Probability and Stochastic Processes
Thể loại research paper
Năm xuất bản 2004
Thành phố Unknown
Định dạng
Số trang 33
Dung lượng 734,39 KB

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Cover times for Brownian motionand random walks in two dimensions By Amir Dembo, Yuval Peres, Jay Rosen, and Ofer Zeitouni* Abstract Let T x, ε denote the first hitting time of the disc o

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Cover times for Brownian motion

and random walks in two dimensions

By Amir Dembo, Yuval Peres, Jay Rosen, and Ofer Zeitouni*

Abstract

Let T (x, ε) denote the first hitting time of the disc of radius ε centered

at x for Brownian motion on the two dimensional torus T2 We prove thatsupx ∈T2T (x, ε)/| log ε|2 → 2/π as ε → 0 The same applies to Brownian mo-

tion on any smooth, compact connected, two-dimensional, Riemannian fold with unit area and no boundary As a consequence, we prove a conjecture,due to Aldous (1989), that the number of steps it takes a simple random walk

mani-to cover all points of the lattice mani-torus Z2

n is asymptotic to 4n2(log n)2

De-termining these asymptotics is an essential step toward analyzing the fractalstructure of the set of uncovered sites before coverage is complete; so far, thisstructure was only studied nonrigorously in the physics literature We also es-tablish a conjecture, due to Kesten and R´ev´esz, that describes the asymptoticsfor the number of steps needed by simple random walk in Z2 to cover the disc

of radius n.

1 Introduction

In this paper, we introduce a unified method for analyzing cover timesfor random walks and Brownian motion in two dimensions, and resolve severalopen problems in this area

1.1 Covering the discrete torus The time it takes a random walk to cover

a finite graph is a parameter that has been studied intensively by probabilists,combinatorialists and computer scientists, due to its intrinsic appeal and itsapplications to designing universal traversal sequences [5], [10], [11], testinggraph connectivity [5], [19], and protocol testing [24]; see [2] for an introduction

*The research of A Dembo was partially supported by NSF grant #DMS-0072331 The research of Y Peres was partially supported by NSF grant #DMS-9803597 The research of

J Rosen was supported, in part, by grants from the NSF and from PSC-CUNY The research

of all authors was supported, in part, by a US-Israel BSF grant.

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to cover times Aldous and Fill [4, Chap 7] consider the cover time for random

walk on the discrete d-dimensional torusZd

n=Zd /nZd, and write:

‘‘Perhaps surprisingly, the case d = 2 turns out to be the hardest

of all explicit graphs for the purpose of estimating cover times.”

The problem of determining the expected cover time T n for Z2

n was posedinformally by Wilf [29] who called it “the white screen problem” and wrote

“Any mathematician will want to know how long, on the average,

it takes until each pixel is visited.”

(see also [4, p 1])

In 1989, Aldous [1] conjectured that T n /(n log n)2 → 4/π He noted that

the upper boundT n /(n log n)2≤ 4/π + o(1) was easy, and pointed out the

dif-ficulty of obtaining a corresponding lower bound A lower bound of the correctorder of magnitude was obtained by Zuckerman [30], and in 1991, Aldous [3]showed that T n / E(T n) → 1 in probability The best lower bound prior to the

present work is due to Lawler [21], who showed that lim infE(T n )/(n log n)2

2/π.

Our main result in the discrete setting, is the proof of Aldous’s conjecture:

Theorem 1.1 If T n denotes the time it takes for the simple random walk

n before coverage is complete

The fractal structure of the uncovered set inZ2

nhas attracted the interest

of physicists, (see [25], [12] and the references therein), who used simulationsand nonrigorous heuristic arguments to study it One cannot begin the rigorousstudy of this fractal structure without knowing precise asymptotics for thecover time; an estimate of cover time up to a bounded factor will not do See[14] for quantitative results on the uncovered set, based on the ideas of thepresent paper

Our proof of Theorem 1.1 is based on strong approximation of randomwalks by Brownian paths, which reduces that theorem to a question aboutBrownian motion on the 2-torus

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1.2 Brownian motion on surfaces For x in the two-dimensional torus

T2, denote by DT2(x, ε) the disk of radius ε centered at x, and consider the

is the ε-covering time of the torus T2, i.e the amount of time needed for the

Brownian motion X t to come within ε of each point in T2 Equivalently,C ε is

the amount of time needed for the Wiener sausage of radius ε to completely

cover T2 We can now state the continuous analog of Theorem 1.1, which isthe key to its proof

Theorem 1.2 For Brownian motion inT2, almost surely (a.s.),

Matthews [23] studied the ε-cover time for Brownian motion on a d

di-mensional sphere (embedded inRd+1 ) and on a d-dimensional projective space

(that can be viewed as the quotient of the sphere by reflection) He calls thesequestions the “one-cap problem” and “two-cap problem”, respectively Part

of the motivation for this study is a technique for viewing multidimensionaldata developed by Asimov [7] Matthews obtained sharp asymptotics for all

dimensions d ≥ 3, but for the more delicate two dimensional case, his upper

and lower bounds had a ratio of 4 between them; he conjectured the upperbound was sharp We can now resolve this conjecture; rather than handlingeach surface separately, we establish the following extension of Theorem 1.2.See Section 8 for definitions and references concerning Brownian motion onmanifolds

Theorem 1.3 Let M be a smooth, compact, connected, two-dimensional, Riemannian manifold without boundary Denote by C ε the ε-covering time of

M , i.e., the amount of time needed for the Brownian motion to come within

(Riemannian) distance ε of each point in M Then

where A denotes the Riemannian area of M

(When M is a sphere, this indeed corresponds to the upper bound in [23],

once a computational error in [23] is corrected; the hitting time in (4.3) there

is twice what it should be This error led to doubling the upper and the lowerbounds for cover time in [23, Theorem 5.7].)

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1.3 Covering a large disk by random walk in Z2 Over ten years ago,Kesten (as quoted by Aldous [1] and Lawler [21]) and R´ev´esz [26] independentlyconsidered a problem about simple random walks inZ2: How long does it take

for the walk to completely cover the disc of radius n? Denote this time by T n.Kesten and R´ev´esz proved that

for certain 0 < a < b < ∞ R´ev´esz [26] conjectured that the limit exists and

has the form e −λ/t for some (unspecified) λ Lawler [21] obtained (1.4) with the constants a = 2, b = 4 and quoted a conjecture of Kesten that the limit equals e −4/t We can now prove this:

Theorem 1.4 If T n denotes the time it takes for the simple random walk

in Z2 to completely cover the disc of radius n, then

lim

n →∞ P(log T n ≤ t(log n)2

) = e −4/t

(1.5)

1.4 A birds-eye view The basic approach of this paper, as in [13], is

to control ε-hitting times using excursions between concentric circles The number of excursions between two fixed concentric circles before ε-coverage is

so large, that the ε-hitting times will necessarily be concentrated near their

conditional means given the excursion counts (see Lemma 3.2)

The key idea in the proof of the lower bound in Theorem 1.2, is to controlexcursions on many scales simultaneously, leading to a ‘multi-scale refinement’

of the classical second moment method This is inspired by techniques fromprobability on trees, in particular the analysis of first-passage percolation byLyons and Pemantle [22] The approximate tree structure that we (implicitly)use arises by consideration of circles of varying radii around different centers;

for fixed centers x, y, and “most” radii r (on a logarithmic scale) the discs

DT2(x, r) and DT2(y, r) are either well-separated (if r  d(x, y)) or almost

coincide (if r  d(x, y)) This tree structure was also the key to our work in

[13], but the dependence problems encountered in the present work are moresevere While in [13] the number of macroscopic excursions was bounded, here

it is large; In the language of trees, one can say that while in [13] we studiedthe maximal number of visits to a leaf until visiting the root, here we study thenumber of visits to the root until every leaf has been visited For the analogiesbetween trees and Brownian excursions to be valid, the effect of the initialand terminal points of individual excursions must be controlled To preventconditioning on the endpoints of the numerous macroscopic excursions to affectthe estimates, the ratios between radii of even the largest pair of concentric

circles where excursions are counted, must grow to infinity as ε decreases to

zero

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Section 2 provides simple lemmas which will be useful in exploiting the

link between excursions and ε-hitting times These lemmas are then used

to obtain the upper bound in Theorem 1.2 In Section 3 we explain how toobtain the analogous lower bound, leaving some technical details to lemmaswhich are proven in Sections 6 and 7 In Section 4 we prove the lattice toruscovering time conjecture, Theorem 1.1, and in Section 5 we prove the Kesten-R´ev´esz conjecture, Theorem 1.4 In Section 8 we consider Brownian motion

on manifolds and prove Theorem 1.3 Complements and open problems arecollected in the final section

2 Hitting time estimates and upper bounds

We start with some definitions Let {W t } t ≥0 denote planar Brownian

motion started at the origin We useT2 to denote the two dimensional torus,which we identify with the set (−1/2, 1/2]2 The distance between x, y ∈ T2,

in the natural metric, is denoted d(x, y) Let X t = W tmod Z2 denote theBrownian motion onT2, where a mod Z2 = [a+(1/2, 1/2)] mod Z2−(1/2, 1/2).

Throughout, D(x, r) and DT2(x, r) denote the open discs of radius r centered

at x, in R2 and in T2, respectively

Fixing x ∈ T2 let τ ξ = inf{t ≥ 0 : X t ∈ ∂DT2(x, ξ) } for ξ > 0 Also let

τ ξ = inf{t ≥ 0 : B t ∈ ∂D(0, ξ)}, for a standard Brownian motion B t on R2

For any x ∈ T2, the natural bijection i = i x : DT2(x, 1/2) → D(0, 1/2) with

i x (x) = 0 is an isometry, and for any z ∈ DT2(x, 1/2) and Brownian motion X t

on T2 with X0 = z, we can find a Brownian motion B t starting at i x (z) such that τ1/2 =τ 1/2 and{i x (X t ), t ≤ τ 1/2 } = {B t , t ≤ τ 1/2 } We shall hereafter use

i to denote i x , whenever the precise value of x is understood from the context,

or does not matter

We start with some uniform estimates on the hitting timesEy (τ r).Lemma 2.1 For some c < ∞ and all r > 0 small enough,



inf

y ∈∂DT2(x,R)Ey (τ r)(2.2)

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such that ∆G x = 1 and F (x, y) = G x (y) + 2π1 log d(x, y) is continuous on

T2 × T2 (c.f [8, p 106] or [16] where this is shown in the more generalcontext of smooth, compact two-dimensional Riemannian manifolds without

boundary) For completeness, we explicitly construct such G x(·) at the end of

Applying the maximum principle for the harmonic function G x + 12e on

T2\ DT2(x, r), we see that for all y ∈ T2\ DT2(x, r),

c = (1/π) + [(1/π) log diam(T2) + 4 sup

x,y ∈T2|F (x, y)|]/ log 4 < ∞ ,

except that we have proved (2.1) so far only for y / ∈ DT2(x, r) To plete the proof, fix x  ∈ T2 with d(x, x  ) = 3ρ > 0 For r < ρ, starting at

com-X0 = y ∈ DT2(x, r), the process X t hits ∂DT2(x, r) before it hits ∂DT2(x  , r).

Consequently, E y (τ r)≤ c| log r| also for such y and r, establishing (2.1).

Turning to constructing G x (y), we use the representationT2= (−1/2, 1/2]2

Let φ ∈ C ∞(R) be such that φ = 1 in a small neighborhood of 0, and φ = 0

outside a slightly larger neighborhood of 0 With r = |z| for z = (z1, z2), let

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Because of the support properties of φ(r) we see that H(z) = ∆h(z) − 1 is a

C ∞ function on T2, and consequently has an expansion in Fourier series

a j,k

2(j2+ k2)cos(2πjz1) cos(2πkz2).

The function F (z) is then a C ∞ function on T2 and it satisfies ∆F = −H.

Hence, if we set g(z) = h(z) + F (z) we have ∆g(z) = 1 for |z| > 0 and g(z) + 2π1 log|z| has a continuous extension to all of T2 The Green’s functionforT2 is then G x (y) = g((x − y)T2)

Fixing x ∈ T2 and constants 0 < 2r ≤ R < 1/2 let

i=0 τ (i) for j = 0, 1, 2, Thus, τ (j) is the length of the j-th

excursion E j from ∂DT2(x, R) to itself via ∂DT2(x, r), and σ (j) is the amount

of time it takes to hit ∂DT2(x, r) during the j-th excursion E j

The next lemma, which shows that excursion times are concentratedaround their mean, will be used to relate excursions to hitting times

Lemma 2.2 With the above notation, for any N ≥ N0, δ0 > 0 small enough, 0 < δ < δ0, 0 < 2r≤ R < R1(δ), and x, x0 ∈ T2,

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Proof of Lemma 2.2 Applying Kac’s moment formula for the first hitting

time τ r of the strong Markov process X t (see [17, equation (6)]), we see that

Fixing x ∈ T2 and 0 < 2r ≤ R < 1/2 let τ = τ(1) and v = π1log(R/r).

Recall that {X t : t ≤ τ R } starting at X0 = z for some z ∈ ∂DT 2(x, r), has the

same law as {B t : t ≤ τ R } starting at B0= i(z) ∈ ∂D(0, r) Consequently,

by the radial symmetry of the Brownian motion B t

By the strong Markov property of X t at τ(0)+ σ(1) we thus have that

Ey

(τ r)≤ E y

(τ ) ≤ E y

(τ r) + τ R R for all y ∈ ∂DT2(x, R) Consequently, with η = δ/6, let R1 (δ) ≤ r0 be small enough so that (2.2) and(2.15) imply

whenever R ≤ R1 It follows from (2.14) and (2.16) that there exists a universal

constant c4 < ∞ such that for ρ = c4| log r|2 and all θ ≥ 0,

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Since τ(0) ≥ 0, using Chebyshev’s inequality we bound the left-hand side of

where the last inequality follows by the strong Markov property of X tat{T j }.

Combining (2.17) and (2.18) for θ = δv/(6ρ), results in (2.10), where C =

By (2.14) and (2.16), there exists a universal constant c8 < ∞ such that for

ρ = c8| log r|2 and all 0 < θ < λ/(2 | log r|),

Lemma 2.3 For any δ > 0 there exist c < ∞ and ε0 > 0 so that for all

Proof of Lemma 2.3 We use the notation of the last lemma and its proof,

with R < R1 (δ) and r = R/e chosen for convenience so that log(R/r) = 1 Let

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i(DT2(x, ε)) = D(0, ε) during n ε excursions, each starting at i(∂DT2(x, r)) =

∂D(0, r) and ending at i(∂DT2(x, R)) = ∂D(0, R), so that

from which the upper bound for (1.2) follows

Set h(ε) = | log ε|2 Fix δ > 0, and set ˜ ε n = e −n so that

(2.26)

Fix x0 ∈ T2and let{x j : j = 1, , ¯ K n }, denote a maximal collection of points

in T2, such that inf =j d(x , x j) ≥ δ˜ε n Let a = (2 + δ)/(1 − 10δ) and A n bethe set of 1≤ j ≤ ¯ K n, such that

T (x j , (1 − δ)˜ε n)≥ (1 − 2δ)ah(˜ε n )/π.

It follows by Lemma 2.3 that

Px0(T (x, (1 − δ)˜ε n)≥ (1 − 2δ)ah(˜ε n )/π) ≤ c ˜ε(1−10δ)a

for some c = c(δ) < ∞, all sufficiently large n and any x ∈ T2 Thus, for all

sufficiently large n, any j and a > 0,

Px0(j ∈ A n)≤ c ˜ε(1−10δ)a

(2.27)

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By Borel-Cantelli, it follows thatA n is empty a.s for all n > n0(ω) and some

n0(ω) <∞ By (2.26) we then have for some n1(δ, ω) <∞ and all n > n1(ω)

and (2.24) follows by taking δ ↓ 0.

3 Lower bound for covering times

Fixing δ > 0 and a < 2, we prove in this section that

In view of (2.24), we then obtain Theorem 1.2

We start by constructing an almost sure lower bound on C ε for a

spe-cific deterministic sequence ε n,1 To this end, fix ε1 ≤ R1(δ) as in Lemma 2.2 and the square S = [ε1 , 2ε1]2 Let ε k = ε1(k!) −3 and n k = 3ak2log k For fixed n ≥ 3, let ε n,k = ρ n ε n (k!)3 for ρ n = n −25 and k = 1, , n Ob- serve that ε n,1 = ρ n ε n , ε n,n = ρ n ε1, and εn,k ≤ ρ n ε n+1 −k ≤ ε n+1 −k for all

1 ≤ k ≤ n Recall the natural bijection i : DT2(0, 1/2) → D(0, 1/2) For

any x ∈ S, let R x

n denote the time until X t completes n n excursions from

i −1 (∂D(x, ε n,n −1 )) to i −1 (∂D(x, ε n,n)) (In the notation of Section 2, if we set

R = ε n,n and r = ε n,n −1, thenR x

n=n n

j=0 τ (j) ) Note that i −1 (∂D(x, ε n,k)) is

just ∂DT2(i −1 (x), ε n,k), but the former notation will allow easy generalization

to the case of general manifolds treated in Section 8

For x ∈ S, 2 ≤ k ≤ n let N x

n,k denote the number of excursions of X t

from i −1 (∂D(x, ε n,k −1 )) to i −1 (∂D(x, ε n,k)) until timeR x

nonoverlap-ping squares of edge length 2ε n = 2ε1 /(n!)3, with x n,j , j = 1, , M ndenoting

the centers of these squares Let Y (n, j), j = 1, , M n, be the sequence ofrandom variables defined by

Y (n, j) = 1 if x n,j is n-successful and Y (n, j) = 0 otherwise Set ¯ q n = P(Y (n, j) = 1) = E(Y (n, j)), noting that this probability is independent of j (and of the value of ρ n)

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The next lemma, which is a direct consequence of Lemmas 6.2 and 7.1,

provides bounds on the first and second moments of Y (n, j), that are used

in order to show the existence of at least one n-successful point x n,j for large

For some C0 < ∞ and all n, if |x n,i − x n,j | ≥ 2ε n,n , then

E(Y (n, i)Y (n, j)) ≤ (1 + C0 n −1 log n)¯ q2n

(3.4)

Further, for any γ > 0 there exists C = C(γ) < ∞ so that for all n and

l = l(i, j) = max{k ≤ n : |x n,i − x n,j | ≥ 2ε n,k } ∨ 1,

In the sequel, we let C m denote generic finite constants that are independent

of n, l, i and j Recall that there are at most C1 ε2n,l+1 ε −2 n points x n,j , j

in D(x n,i , 2ε n,l+1 ) Further, our choice of ρ n guarantees that (ε n,n /ε n)2

C2M n n −50 Hence, it follows from (3.5) that for n − 1 ≥ l ≥ 1,

V l := (M n q¯n)−2

M n



i=j=1 l(i,j)=l

E Y (n, i)Y (n, j)

(3.7)

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Combining this with (3.6) and (3.8), we see that

The next lemma relates the notion of n-successful to the ε n,1-hitting time

Lemma 3.2 For each n let V n be a finite subset of S with cardinality bounded by e o(n2) There exists m(ω) < ∞ a.s such that for all n ≥ m and all

R = ε n,n , and r = ε n,n −1 so that log(R/r) = 3 log n and R > r 0.8, we see that

for some C > 0 that is independent of n,

Consequently, the sum of P x over all x ∈ V n and then over all n is finite, and

the Borel-Cantelli lemma then completes the proof of Lemma 3.2

Taking V n = {x n,k : k = 1, , M n }, and the subsequence n(j) = j(log j)3, it follows from (3.9), (3.10) and the Borel-Cantelli lemma that a.s

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Remark. We note for use in Section 5 that essentially the same proofshows that for anya < 2, almost surely,

n −4 times its previous value Clearly (3.6) still holds, with perhaps a different

γ > 0 Also, we now have only (ε n,n /ε n)2≤ C2M n n −42, but this is enough toestablish (3.7) The rest of the proof follows as before

4 Proof of the lattice torus covering time conjecture

To establish Theorem 1.1 it suffices to prove that for any δ > 0

since the complementary upper bound onT n is contained in [4, Cor 25, Chap.7] (see also the references therein) Our approach is to use Theorem 1.2 to-gether with the strong approximation results of [15] and [20]

Fix γ > 0 and let ε n = 2n γ −1 Then by Theorem 1.2 for all n ≥ N0 with

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hence by (4.3) with probability at least 1− 2δ we have that

avoids some disc of radius n γ is at least 1− 2δ, which implies (4.1).

Let D r = D(0, r) ∩ Z2 denote the disc of radius r in Z2 and define itsboundary

∂D r ={z /∈ D r |z − y| = 1 for some y ∈ D

r }.

Let φ n = (log n)2/ log log n and let N n denote the number of excursions

inZ2 from ∂D2n to ∂D n(log n)3 after first hitting ∂D n(log n)3, that is needed to

cover D n By [21, Theorem 1.1], it suffices to show that

Remark Though not needed for our proof of Theorem 1.4, it is not hard

to modify the proof of Lemma 5.1 so as to show thatN n /φ n → 2

where θ := inf {t ≥ 0 : W t ∈ ∂A r }, and W t is a planar Brownian motion,

starting at W0 = z ∈ A r A preliminary step in proving Lemma 5.1 is the

following estimate about K(z, u) when |z|  r = |u|.

Lemma 5.2 There exists finite c > 2 such that if cr ≤ |z| < 1/(2c), then

sup

{u:|u|=r} K(z, u) ≤ 1 + 40r log(2r)

|z| log(2|z|)

inf

{u:|u|=r} K(z, u).

(5.2)

...

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Remark. We note for use in Section that essentially the same proofshows that for anya...(3.7)

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Combining this with (3.6) and (3.8), we see that

The... Then by Theorem 1.2 for all n ≥ N0 with

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hence by (4.3) with

Ngày đăng: 14/02/2014, 17:20

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