Annals of Mathematics Uniform bounds for the bilinear Hilbert transforms, I By Loukas Grafakos and Xiaochun Li... Uniform bounds for the bilinear Hilbert transforms, IBy Loukas Grafako
Trang 1Annals of Mathematics
Uniform bounds for the
bilinear Hilbert transforms, I
By Loukas Grafakos and Xiaochun Li
Trang 2Uniform bounds for the bilinear Hilbert transforms, I
By Loukas Grafakos and Xiaochun Li*
p1+p2 < 2 Combining this result with the main
result in [9], we deduce that the operators H 1,α map L2(R)×L ∞(R)→ L2(R)
uniformly in the real parameter α ∈ [0, 1] This completes a program initiated
by A Calder´on
1 Introduction
The study of the Cauchy integral along Lipschitz curves during the period1965–1995 has provided a formidable impetus and a powerful driving force forsignificant developments in euclidean harmonic analysis during that period andlater The Cauchy integral along a Lipschitz curve Γ is given by
where h is a function on Γ, which is taken to be the graph of a Lipschitz
function A : R → R Calder´on [2] wrote CΓ(h)(z) as the infinite sum
Trang 3reducing the boundedness of CΓ(h) to that of the operators C m (f ; A) with constants having suitable growth in m The operators C m (f ; A) are called the commutators of f with A and they are archetypes of nonconvolution singular
integrals whose action on the function 1 has inspired the fundamental work
on the T 1 theorem [5] and its subsequent ramifications The family of bilinear
com-with derivative A in L ∞ In fact, in the mid 1960’s Calder´on observed that
the linear operator f → C1(f ; A) can be written as the average
via a different approach, the issue of the uniform boundedness of the operators
H 1,α from L2(R)× L ∞ (R) into L2(R) remained open up to now The purpose
of this article and its subsequent, part II, is to obtain exactly this, i.e the
uniform boundedness (in α) of the operators H 1,αfor a range of exponents thatcompletes in particular the above program initiated by A Calder´on about 40years ago This is achieved in two steps In this article we obtain bounds for
H 1,α from L p1(R)×L p2(R) into L p (R) uniformly in the real parameter α when
2 < p1, p2 < ∞ and 1 < p = p1p2
p1+p2 < 2 In part II of this work, the second
author obtains bounds for H 1,α from L p1(R)× L p2(R) into L p(R), uniformly
in α satisfying |α − 1| ≥ c > 0 when 1 < p1, p2 < 2 and 23 < p = p1p2
p1+p2 < 1.
Interpolation between these two results yields the uniform boundedness of H 1,α
from L p(R)×L ∞ (R) into L p(R) for 43 < p < 4 when α lies in a compact subset
of R This in particular implies the boundedness of the commutator C1(· ; A)
on L p(R) for 43 < p < 4 via the Calder´on method described above but also hasother applications See [9] for details We note that the restriction to compact
subsets of R is necessary, as uniform L p × L ∞ → L p bounds for H 1,α cannot
Boundedness for the operators H 1,α was first obtained by M Lacey and
C Thiele in [7] and [8] Their proof, though extraordinary and pioneering,
gives bounds that depend on the parameter α, in particular that blow up polynomially as α tends to 0, 1 and ±∞ The approach taken in this work is
based on powerful ideas of C Thiele ([10], [11]) who obtained that the H 1,α’s
map L2(R)× L2(R)→ L 1, ∞ (R) uniformly in α satisfying |α − 1| ≥ δ > 0.
Trang 4The theorem below is the main result of this article.
Theorem Let 2 < p1, p2 < ∞ and 1 < p = p1p2
p1+p2 < 2 Then there is a constant C = C(p1, p2) such that for all f1, f2 Schwartz functions on R,
sup
α1,α2∈R H α1,α2(f1, f2) p ≤ C f1 p1f2 p2.
By dilations we may take α1 = 1 It is easy to see that the boundedness
of the operator H 1, −α on any product of Lebesgue spaces is equivalent to that
considerations, it suffices to obtain uniform bounds near only one of the three
‘bad’ directions α = −1, 0, ∞ of H 1, −α In this article we choose to work
with the ‘bad’ direction 0 This direction corresponds to bilinear multipliers
whose symbols are characteristic functions of planes of the form η < α1ξ For
simplicity we will only consider the case where α1 = 2m , m ∈ Z+ The ments here can be suitably adjusted to cover the more general situation where
uniformly in m ≥ 2200 where p1, p2, p are as in the statement of the theorem.
The rest of the paper is devoted to the proof of (1.2) In the following
sections, L = 2100 will be a fixed large integer We will use the notation|S| for
the Lebesgue measure of set S and S c for its complement By c(J ) we denote the center of an interval J and by AJ the interval with length A |J| (A > 0)
and center c(J ) For J, J sets we will use the notation
J < J ⇐⇒ sup
x ∈J x ≤ inf
x ∈J x.
The Hardy-Littlewood maximal operator of g is denoted by M g and M p g will
be (M |g| p)1/p The derivative of order α of a function f will be denoted by
D α f When L p norms or limits of integration are not specified, they are to
be taken as the whole real line Also C will be used for any constant that
Trang 5de-pends only on the exponents p1, p2 and is independent of any other parameter,
in particular of the parameter m Finally N will denote a large (but fixed)
integer whose value may be chosen appropriately at different times
Acknowledgments. The authors would like to thank M Lacey for manyhelpful discussions during a visit at the Georgia Institute of Technology Theyare grateful to C Thiele for his inspirational work [10] and for some help-ful remarks They also thank the referee for pointing out an oversight in aconstruction in the first version of this article
2 The decomposition of the bilinear operator T m
We begin with a decomposition of the half plane η < 2 m ξ on the ξ-η plane.
We can write the characteristic function of the half plane η < 2 m ξ as a union
of rectangles of size 2−k × 2 −k+m as in Figure 1 Precisely, for k, l ∈ Z we set
which provides a (nonsmooth) partition of unity of the half-plane η < 2 m ξ.
Next we pick a smooth partition of unity {Ψ (r)
k,l (ξ, η) } k,l,r of the half-plane
η < 2 m ξ with each Ψ (r) k,l supported only in a small enlargement of the rectangle
J1(r) (k, l) × J (r)
2 (k, l) and satisfying standard derivative estimates Since the
functions Ψ(r) k,l (ξ, η) are not of tensor type, (i.e products of functions of ξ and functions of η) we apply the Fourier series method of Coifman and Meyer [4,
Trang 6rectangle size
2−k × 2 −k+m
ξ
rectangle t
of ype 2
rectangle t
of ype 1
rectangle t
convenience, we will drop the dependence of these functions on r and we will concentrate on the case n = (n1, n2) = (0, 0) In the cases n
mial appearance of |n| in the estimates will be controlled by the rapid decay
Trang 7of C(n), while the exponential functions in (2.1) and (2.2) can be thought of
as almost “constant” locally (such as when n1 = n2 = 0), and thus a small
adjustment of the case n = (0, 0) will yield the case for general n in Z2.Based on these remarks, we may set Φj,k,l = Φj,k,l,0and it will be sufficient
to prove the uniform (in m) boundedness of the operator T m0 defined by
The representation of T m0 into a sum of products of functions of ξ and η will be
crucial in its study If follows from (2.1) and (2.2) that there exist the followingsize estimates for the functions Φ1,k,l and Φ2,k,l
|Φ 1,k,l (x) | ≤ C N2−k(1 + 2−k |x|) −N ,
(2.4)
|Φ 2,k,l (x) | ≤ C N2−k+m(1 + 2−k+m |x|) −N
(2.5)
for any N ∈ Z+ The next lemma is also a consequence of (2.1) and (2.2)
Lemma 1 For all N ∈ Z+, there exists C N > 0 such that for all f ∈
(2.7)
where C N is independent of m.
Proof. To prove the lemma we first observe that whenever Φl ∈ S
has Fourier transform supported in the interval [2l − 3, 2l + 3] and satisfies
supl D αΦl ∞ ≤ C α for all sufficiently large integers α, then we have
Once (2.8) is established, we apply it to the function Φl (x) = 2 kΦ1,k,l(2k x),
which by (2.1) satisfies |D αΦl (ξ) | ≤ C α, to obtain (2.6) Similarly, applying(2.8) to the function Φl (x) = 2 k −mΦ2,k,l(2k −m x), which by (2.2) also satisfies
|D αΦl (ξ) | ≤ C α, we obtain (2.7).
Trang 8By a simple translation, it will suffice to prove (2.8) when x = 0 Then
3 The truncated trilinear form
Let ψ be a nonnegative Schwartz function such that ψ is supported in
[−1, 1] and satisfies ψ(0) = 1 Let ψ k (x) = 2 −k ψ(2 −k x) For E ⊂ R and k ∈ Z
Note that ψ 1,k , ψ 2,k , and ψ 3,k depend on the set E but we will suppress this
dependence for notational convenience, since we will be working with a fixed
set E Also note that the functions ψ 2,k and ψ 3,k depend on m, but this
dependence will also be suppressed in our notation The crucial thing is that
all of our estimates will be independent of m Define
rectangle in which the Fourier transforms of Φ1,k,l and Φ2,k,l are supported.)One easily obtains the size estimate
|Φ 3,k,l (x) | ≤ C2 −k+m(1 + 2−k+m |x|) −N .
(3.5)
Trang 9Because of the assumption on the indices p1, p2, there exists a 2 < p3< ∞
Lemma 2 will be proved in the next sections Now, we have
Proof To prove (1.2), it will be sufficient to prove that for all λ > 0,
m (f1, f2)| > 2}, and assuming |G| ≥ 1 (otherwise there is
nothing to prove) choose f3∈ S with f3 L ∞ (E c)≤ 1, supp f3 ⊂ E c , and
{x ∈ R : M p3(M f3)(x) > 2 } is empty Now define
Trang 10Therefore, to prove (3.7), we only need to show that
k∈Zl ∈Z
(1−
for all N > 0 Therefore, (3.11) can be estimated by
Similar reasoning works for (3.12) This completes the proof of (3.9) andtherefore of Lemma 3
Trang 11We now set up some notation For k, n ∈ Z, define I k,n = [2k n, 2 k (n + 1)]
For an integer r with 0 ≤ r < L, let Z r ={ ∈ Z : = κL+r for some κ ∈ Z}.
Also for S ⊂ Z r × Z × Z r we let S k,l ={n ∈ Z : (k, n, l) ∈ S} and define
For simplicity we will only consider the case where m ∈ Z0 The argument
below can be suitably adjusted to the case where m has a different remainder when divided by L We will therefore concentrate on proving Lemma 2 for the
expression ΛE,S (f1, f2, f3) when m ∈ Z0 To achieve this goal, we introducethe grid structure
Definition 1 A set of intervalsG is called a grid if the condition below
then it will be called a central grid.
Given S ⊂ Z r × Z × Z r and s = (k, n, l) ∈ S we set I s = I k,n For eachfunction Φj,k,l and each n ∈ Z we define a family of intervals ω j,s , s = (k, n, l)
∈ S so that conditions (3.19)–(3.25) below hold: Say that Φ1,k,l (ξ) Φ2,k,l (η) is supported in a small neighborhood of a rectangle of type r = 1 Then we define ω j,ssuch that
Trang 12supp Φ3,k,l ⊂ [−(1 + 2 −m )a, −(1 + 2 −m )b), where [a, b) = ω 3,s ,
These properties are trivially adjusted when Φ1,k,l (ξ) Φ2,k,l (η) is supported in
a small neighborhood, a rectangle of type r = 2 or r = 3.
As in [7], we prove the existence of ω j,s by induction If S is nonempty, pick
s0 = (k, n, l) ∈ S such that k is minimal and define S = S \{s0} By induction,
we may assume that for any s ∈ S there exists a ω j,s so that the collection
of all such intervals satisfies (3.19)–(3.25) Now we try to define ω j,s0 so that
(3.19)–(3.25) still hold Let [a1, b1) be an interval with length (1 + 2−2L)2−kwhich contains supp Φ1,k,l And for j = 2, 3, let [a j , b j) be an interval withlength (1 + 2· 2 −2L)2−k+m which contains supp Φ
j,k,l By (3.22), we know thatsupp Φ3,k,l ⊂ [−(1+2 −m )a3, −(1+2 −m )b3) Define ω j,s
0,1 as the union of [a j , b j)
and all intervals 5ω j,s with s ∈ S which satisfy dist(ω j,s , [a j , b j)) ≤ 2|ω j,s |
and ω j,s be the next smaller interval in S Inductively we define ω j,s0,l for
l ≥ 1 Let ω j,s0 =
l ≥1 ω j,s0,l It is easy to verify conditions (3.19)–(3.25) for
ω j,s0 This completes the proof of the existence of a grid structure
Furthermore, we have the following geometric picture for ω j,s
Lemma 4 For s, s ∈ S and ω j,s j,s , the following properties hold :
(1) If ω 1,s ⊂ ω 1,s , then ω j,s < ω j,s and 12|ω j,s | < dist(ω j,s , ω j,s ) < 2 |ω 2,s | for j = 2, 3.
(2) If ω j,s ⊂ ω j,s for j = 2, 3, then ω 1,s < ω 1,s and 18|ω 1,s | < dist(ω 1,s , ω 1,s )
Trang 13As in [10] we give the following definition.
Definition 2 A subset S of Z r ×Z×Z r is called convex if for all s, s ∈ S,
s ∈ Z r × Z × Z r , j ∈ {1, 2} with I s ⊂ I s ⊂ I s and ω j,s ⊂ ω j,s ⊂ ω j,s, we
have s ∈ S.
It is sufficient to prove bounds on ΛE,S for all finite convex sets S of triples
of integers, provided the bound is independent of S and of course m.
4 The selection of the trees
Definition 3 Fix T ⊂ S and t ∈ T If for any s ∈ T , we have I s ⊂ I t
and ω j,s ⊃ ω j,t , then we call T a tree of type j with top t Now, T is called a
maximal tree of type j ∈ {1, 2} with top t in S if there does not exist a larger
tree of type j with the same top strictly containing T Let T be a maximal tree
of type j
tree of type i with top t in S by T
Lemma 5 Let S ⊂ Z r × Z × Z r be a convex set and T ⊂ S be a maximal tree of type j ∈ {1, 2} with top t in S Then T is a convex set.
Proof Let s, s ∈ T , s ∈ Z r × Z × Z r , i ∈ {1, 2} with I s ⊂ I s ⊂ I s and
from Lemma 4 that i = j Using that I s ⊂ I s ⊂ I t , ω j,t ⊂ ω j,s ⊂ ω j,s , and
the maximality of T , we obtain that s ∈ T , hence the convexity of T follows.
Lemma 6 Let S ⊂ Z r × Z × Z r be a convex set and T be a maximal tree
of type j ∈ {1, 2} with top t in S Then S\(T T ) is convex.
Proof Assume that S\(T T ) is not convex Then there exist s, s ∈ S\(T T ), s ∈ T T , i ∈ {1, 2} with I s ⊂ I s ⊂ I s and ω i,s ⊂ ω i,s ⊂ ω i,s
If s ∈ T , then I s ⊂ I t and ω j,t ⊂ ω j,s Since s is not in T , we have i
By Lemma 4, we have dist(ω i,t , ω i,s ) < 2 |ω j,s | Since 5ω i,s ⊂ ω i,s we have
ω i,t ⊂ ω i,s Thus s ∈ T , which is a contradiction.
For a given subset T of S we define T k,l to be the set
{n ∈ Z : (k, n, l) ∈ T }.
If T is a tree of type j for j ∈ {1, 2, 3} and k ∈ Z r, then there is at most
Φj,k,T = Φj,k,l Otherwise, let T k = ∅ and Φ j,k,T = 0 For brevity, we write
(k, n) ∈ T if and only if there exists an l ∈ Z r with (k, n, l) ∈ T Thus
Trang 14identifying trees with sets of pairs of integers, we will use this identificationthroughout.
Therefore, if (k, n, l) ∈ T , we can write ω j,k,n,l = ω j,k,l = ω j,k,T, and
Let t = (k T , n T , l T ) be the top of T We write I T = I k T ,n T and ω j,T = ω j,k T ,T
For a tree T of type 2 (or 3) with top t and k ∈ Z r , define θ j,k,T+ and θ j,k,T −
accordance with the definitions of φ j,k,n and ψ j,k we define the functions
Let ∆k be the set of all connected components of E k \E k+L Obviously ∆k is
a set of intervals Observe that if J ∈ ∆ k, then 2k ≤ |J| < 2 k+L, and
Trang 15We now describe a procedure for selecting a collection of trees T µ,i,j,l ν and
where T µ,i,j,l ν , T µ,i,j,l ν are defined as follows:
Let l ≥ 0 be an integer and assume that we have already defined T ν
µ,i,j,λ,
T µ,i,j,λ ν for λ < l If one of the sets T µ,i,j,λ ν , T µ,i,j,λ ν with λ < l is empty, then let
T µ,i,j,l ν = T µ,i,j,l ν =∅ Otherwise, let F denote the set of all trees T of type i
which satisfy conditions (1)–(8) below:
and T is a maximal tree of type i in S µ −1 \
λ<l
(T ν µ,i,j,λ T ν
µ,i,j,λ)
(2) If (i, j, ν) = (1, 1, 1), then for (k, n) ∈ T , one of the following inequalities
holds:
φ ∗ 1,k,n ψ 1,k ∗ (f1∗ Φ 1,k,l)
(5) If i = 2 or 3, j = 2 or 3, ν = 2, then there exists ˜ k ∈ {−L, 0, L, 2L, 3L, 4L}
such that, for (k, n) ∈ T , one of the following inequalities holds:
Trang 16j,k,T)2 2
T µ,i,j,l ν =∅ Otherwise, we select T ν
µ,i,j,l and T µ,i,j,l ν as follows
(9) If (i, j, ν) ∈ {(1, 2, 1), (1, 3, 1), (2, 2, 4), (2, 3, 4), (3, 2, 4), (3, 3, 4)}, then
se-lect T µ,i,j,l ν ∈ F such that for any T ∈ F,
ω j,T ν µ,i,j,l ≯ ω j,T
(10) If (i, j, ν) ∈ {(2, 1, 1), (3, 1, 1), (2, 2, 3), (2, 3, 3), (3, 2, 3), (3, 3, 3)}, then
se-lect T µ,i,j,l ν ∈ F such that for any T ∈ F,
ω j,T ν ≮ ω j,T
(4.17)
Trang 17Let T µ,i,j,l ν be the maximal tree of type i with top t in
Lemma 5 and Lemma 6, we have that S µ , T µ,i,j,l ν and T µ,i,j,l ν are convex
Lemma 7 For µ ≥ 0, (i, j, ν) ∈ H,
l
|I T ν µ,i,j,l | ≤ C2 10ηpj µ
2µ(4.18)
where C, C q1 are independent of m.
The core of the proof consists of the proofs of these lemmata These will
be given in the next section We now state and prove one more lemma whichwill allow us to conclude the proof of (1.2), assuming the validity of Lemmas 7and 8
Lemma 9 Let µ ≥ 0, T ⊂ S µ −1 be a tree of type j ∈ {1, 2, 3}, P ⊂ S µ −1,
Proof Notice there exists at most one l such that T k,l
Trang 19We now deduce the proof of (1.2) using assumed Lemmas 7 and 8, andLemma 9.
5 Some technical material
In this section we prove a variety of technical facts that will be used inthe proofs of Lemmas 7 and 8 presented in the next sections
Lemma 10 For any (k, n, l) ∈ S there exists the following:
φ ∗ 1,k,n (f1∗ Φ 1,k,l)
2 ≤ C
inf
Trang 20Φ1,k,l(·)e −2πic(ω 1,k,l)(·) (x) ≤ C 2 −2k(1 + 2−k |x|) −N .
Using this estimate and a similar argument as before we obtain (5.2)
We now prove (5.3) assuming that I k,n ⊂ E; otherwise (5.3) follows
immediately from (5.1) and from the fact that M f1(x) ≤ M p1f1(x) Pick
x ∈2AI k,n
M p1f1(x)
2
|I k,n | ≤ C|I k,n |.
This completes the proof of (5.3) The proof of (5.4) is similar
Applying the same idea and the fact that the Littlewood-Paley square
function is bounded from L2 to L2, we can prove the following
Lemma 11 For any tree T of type 1 and any j ∈ {2, 3},
(k,n) ∈T
φ ∗ j,k,n (f j ∗ Φ j,k,T)2
2
1 2
2
1 2
≤ C|I k T ,n T |1
2.
(5.6)
Similarly we obtain the following lemmas whose proofs we omit
Lemma 12 For any tree T of type j, j ∈ {2, 3},
(k,n) ∈T
φ ∗ 1,k,n (f1∗ Φ 1,k,T)2
2
1 2
Trang 21Lemma 13 For (k, n, l) ∈ S, ˜k ∈ {−L, 0, L, 2L, 3L, 4L}, and j ∈ {2, 3},
φ ∗ j,k+˜ k,n (f j ∗ Φ j,k+˜ k,l)
2≤ C|I k,n |1
2,
(5.14)
φ ∗ 1,k,n ψ ∗ 2,k+m+˜ k (f j ∗ Φ j,k+m+˜ k,l)
j,k,T)2 2
1 2
2
1 2
j,k,T)2 2
1 2
2
1 2
≤ C|I k T ,n T |1
.
(5.22)
Trang 22Proof We prove (5.22) first Since
ρ k −m,J (f j ∗ Φ j,k+˜ k,T)2
2≤
1(1 + 2−k+m dist(x, J )) N
(1+2−k+m |z0− x|)2
x ∈I T
M2f j (x)
2
,
which proves (5.21) and thus completes the proof of Lemma 15
The following lemma is just a version of the boundedness of the
Littlewood-Paley square function from L ∞ to BMO Its proof follows standard argumentsand is also omitted
Trang 23Lemma 16 Let j ∈ {2, 3} and T ⊂ S be a convex tree of type j Then
ψ ∗ j,k (f j ∗ Φ j,k,l)
where C is independent of m and BMO denotes dyadic BMO.
6 The size estimate for the trees
Having proved all these preliminary lemmas we now concentrate on theproof of Lemma 8 This section is entirely devoted to its proof
We begin by showing (4.19) For a tree T of type 1 and T ⊂ S µ,
≤ C sup (k,n) ∈T
φ ∗ 1,k,n ψ 1,k ∗ (f1∗ Φ 1,k,T)
∞2−
µ p22−
µ p3 |I T |.
This completes the proof of (4.19) for trees of type 1 We now turn our tion to the proof of (4.20) Let
... Z< /i> 0 To achieve this goal, we introducethe grid structureDefinition A set of intervals G is called a grid if the condition below< /i>
then it will be called... r with (k, n, l) ∈ T Thus< /i>
Trang 14identifying trees with sets of pairs of integers, we will... class="page_container" data-page ="1 3">
As in [10] we give the following definition.
Definition A subset S of Z r ×Z×Z r is called convex if for all