Engineering Tribology 2E Episode 5 pptx

... [N] 1. 757 5 ×10 4 -0.793 2.033 2 .59 6 1.042 0.884 -1 .51 0 - - 1.108 - 8 H [W] 2.79 15 10 3 -0 .57 9 1 .53 0 0.873 2 .50 0 1.642 -0.2 25 - - 9 ε 1. 051 6× 10 2 0.399 -1.040 1.372 -0 .53 9 -0. 458 0.7 65 - - 10 T max ... 10 1 υ 37.8°C −1.1 υ 93.3°C 2.46 L 2 .51 5 D 0 .56 3 N 0 .52 8 c −1.09 T S −0.383 () ε 1 − ε 2 1.3 85 or row 7: W = 1. 757 5 × 10 4 υ 37.8°C −0.793 υ 93.3°C 2.033 L 2...

Ngày tải lên: 13/08/2014, 16:21

... described below. HYDRODYNAMIC LUBRICATION 153 0 0.1 0.2 0.3 0.4 0 .5 0.6 0.7 0.8 0.9 1.0 0.01 0.02 0.03 0.04 0. 05 0.06 0.08 0.1 0.2 0.3 0.4 0 .5 0.6 0.8 1 2 3 4 5 6 8 10 20 30 40 50 60 80 100 L D = ∞ = 1 1 2 = 1 4 = 1 8 = 0.02 0.03 0.04 0. 05 0.06 0.08 0.1 0.2 0.3 0.4 0 .5 0.6 0.8 1 2 3 4 5 6 8 10 20 0.004 0.0 05 0.006 0.008 0.01 1 8 Ocvirk W/L Uη ∆ ... K) (4 .57 ) Substitut...

Ngày tải lên: 13/08/2014, 16:21

... of mid-ordinate 15 ° 10 sin 15 ° D 2 .58 8 V 45 ° 10 sin 45 ° D 7.071 V 75 ° 10 sin 75 ° D 9. 659 V 1 05 ° 10 sin 1 05 ° D 9. 659 V 1 35 ° 10 sin 1 35 ° D 7.071 V 1 65 ° 10 sin 1 65 ° D 2 .58 8 V Sum of mid-ordinates ... speed/time is shown in Fig. 20.3. 30 25 Graph of speed/time 20 15 Speed (m/s) 10 5 0 12 3 Time (seconds) 45 6 2 .5 4.0 7.0 15. 0 5. 5 8. 75 10. 75...

Ngày tải lên: 13/08/2014, 08:21

... 000 2 50 0 3 000 3 50 0 4 000 35 40 45 50 60 70 80 90 2 2 .5 3 3 .5 4 4 .5 5 6 7 8 9 10 15 20 25 30 35 40 45 50 60 70 80 90 1.9 1.8 1.7 1.6 1 .5 1.4 1.3 1.2 25 30 35 40 45 50 60 70 80 90 100 150 200 250 300 350 400 450 30 35 40 45 50 60 70 80 90 100 150 200 250 300 350 400 100 120 FIGURE ... cS 100 150 200 250 300 350 400 450 50 0 600 700 800...

Ngày tải lên: 13/08/2014, 16:21

... equations (5. 37), (5. 38) and (5. 39), i.e.: v = z η dz ⌠ ⌡ 0 h ⌠ ⌡ 0 h dz η dp dy z η ⌠ ⌡ z 0 dz − dz η ⌠ ⌡ 0 z ()( ) (5. 45) Substituting for ‘M’ equation (5. 45) simplifies to: v = M dp dy (5. 46) An ... defined as follows: 244 ENGINEERING TRIBOLOGY 1 .5 2 .5 0 0.1 Groove len g th/axial bearin g len g th Dimensionless load 2 0.2 0.3 0.4 0 .5 0.6 0.7 0.8 0.9 1 0...

Ngày tải lên: 13/08/2014, 16:21

... 100 200 50 0 1000 2000 50 00 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 2 × 10 6 5 × 10 6 10 7 200 50 0 1000 2000 50 00 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 100 50 20 10 Piezoviscous-elastic Piezoviscous-rigid Lubrication ... 0. 25 µW U A − U B  Ka 0.1 < L < 5 T f a = 0 .5 NL = α π 4 or qa K T f a = 0. 25 µW U A − U B  Ka α ranges...

Ngày tải lên: 13/08/2014, 16:21