Shallow Liquid Simulation Using Matlab (2001 Neumann) Episode 4 pdf
Tài liệu Control Systems Simulation using Matlab and Simulink pptx
... required. Control Systems Simulation Using Matlab and Simulink 1 Introduction In ME134, we will make extensive use of Matlab and Simulink in order to design, analyze and simulate the response of control ... order system 6 “Hands-on” Design of Control Systems “Hands on Design systems refers to directly working with the system to be controlled and trying a variety...
Ngày tải lên: 12/12/2013, 07:15
vibration simulation using matlab and ansys - michael r hatch
... linear imaginary versus linear freq frequency, rad/sec imaginary magnitude Figure 3.12: Real and imaginary magnitude versus linear frequency. Comments on real versus linear frequency, imaginary ... 10 -1 10 0 10 1 -4 0 -2 0 0 20 z11, z33 linear real mag versus log freq real magnitude 10 -1 10 0 10 1 -1 0 -5 0 z11, z33 linear imaginary versus log freq frequency, rad/...
Ngày tải lên: 08/04/2014, 10:29
shallow liquid simulation using matlab 2001 neumann pot
... Homework 2 Shallow Liquid Simulation Erik Neumann 610 N. 65th St., Seattle, WA 98103 erikn@MyPhysicsLab.com November 19, 2001 Abstract A model of shallow fluid behavior is evaluated using a variety ... be confident that A is non-singular. If K(A) is very large, then A is nearly singular. It turns out (using the Matlab command condest) that A in equation (25) has a very large co...
Ngày tải lên: 27/06/2014, 18:20
Shallow Liquid Simulation Using Matlab (2001 Neumann) Episode 4 pdf
... uu xy ) + (uv) y y = fv y (45 ) v tx + 2(v x v y + vv xy ) + (uv) xx = −fu x (46 ) Expand some derivatives u y t + 2u y u x + 2uu xy + uv y y + 2u y v y + u y y v = fv y (47 ) v xt + 2v x v y + 2vv xy + ... u y y v = fv y (47 ) v xt + 2v x v y + 2vv xy + uv xx + 2u x v x + u xx v = −fu x (48 ) Subtracting (47 ) from (48 ) and rearranging gives us (v xt − u y t ) + (uv xx − uu xy ) + (vv...
Ngày tải lên: 12/08/2014, 07:22
Aircraft Design Projects Episode 4 pdf
... kg A B C D Fig. 4. 13 Payload/range diagram (developments) “chap 04 — 2003/3/10 — page 74 — #29 74 Aircraft Design Projects above, in a new estimation of MTOM: MTOM = 110 520/(1 − 0 .49 5 − 0 .41 3) = 1 14 348 ... 91 21 550 500 45 0 40 0 12 10 8 14 20 19 18 17 16 Fig. 4. 20 Trade-off study: cruise L/D ratio 46 550 500 45 0 40 0 12 10 8 14 44 42 40 38 32 34 36 1000...
Ngày tải lên: 13/08/2014, 15:21
Failure Analysis Case Studies II Episode 4 pdf
... = 2.7m p = 1 540 kgm-3 g = 9.81 m s-2 ozul = 2.54Nmm-’ = 2. 54~ 106Nm-* The equation for s becomes 2.7 x 1 540 x 9.81 x h 2 x 2. 54 x 106 S= 1.82~ = 1 .46 ~ 10-2h (3) ... of a silo. Engineering Failure Analysis 1997 ;44 9. [3] DVS 2205 is published by the publishing arm of the German Welding Institute (Deutscher Verlag fur SchweiB- [4] Roark’s Formul...
Ngày tải lên: 13/08/2014, 15:22
Handbook of Polymer Synthesis Second Edition Episode 4 pdf
... random copolymerization with styrene. Mole% n-butyl acrylate 10 À3 M w 10 À3 M n PDI Conversion/% 24. 7 32.5 24. 6 1.32 89.3 43 .5 38.2 24. 8 1. 54 83.0 64. 1 36 .4 24. 4 1 .49 65.2 81.2 10.6 6.1 1.73 33 .4 Copyright ... butanone [49 5] or ethyl methyl ketone [47 0 ,47 6] with AIBN [49 6 49 9] and dioxane with benzoyl peroxide [47 4 ,48 4,500,503]. In benzene as solvent the resulting...
Ngày tải lên: 13/08/2014, 16:21
KUNDU Fluid Mechanics 2 Episode 4 pdf
... 'Itucsdcll, C. A. (19 52) . Stokes' principle of viscosity. JoumZ oJRationol Mechanics ud Analysi.s 1: physical Journul131: 4 42 4 47 . Univemity Press. 22 8 -23 1. Supplernim?al Reading ... (5 .22 ) can be written as -V&nqi&ijkWk,jq = -V(&jSqk - &~haqj)wk.jq = -vWk,nk + vOn,jj = v%,jj. (5 .25 ) If we use Eqs. (5 .23 H5 .25 ),...
Ngày tải lên: 13/08/2014, 16:21