Engineering Mechanics Statics - Examples Part 5 docx

Engineering Mechanics Statics - Examples Part 5 docx

Engineering Mechanics Statics - Examples Part 5 docx

... publisher. Engineering Mechanics - Statics Chapter 4 1 2 w 1 ba 2b 3 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 1 2 w 2 c 2c 3 − M−= a b ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ Find ab,()= a b ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 1 .53 9 5. 6 25 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ m= Problem 4-1 48 Replace ... without permission in writing from the publisher. Engineering Mechanics - Statics Chapter 4 F 1 60 lb= a 2ft= F 2 85 lb= b 3ft= F 3 25 lb= c 6ft= θ 45 deg= d 4...

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Engineering Mechanics Statics - Examples Part 7 docx

Engineering Mechanics Statics - Examples Part 7 docx

... publisher. Engineering Mechanics - Statics Chapter 6 F AB F AF F BC F BF F FC F FE F ED F EC F CD ⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ 377.1− 189.7 266.7− 266.7 188.6 56 .4 56 .4 0.0 188.6− ⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ lb= Positive ... any form or by any means, without permission in writing from the publisher. Engineering Mechanics...

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Engineering Mechanics Statics - Examples Part 14 docx

Engineering Mechanics Statics - Examples Part 14 docx

... components are indicated below. Given: a 0. 75 m= M 1 25 kg= b 1. 25 m= M 2 80 kg= c 0 .5 m= M 3 30 kg= d 0. 75 m= M 4 1 05 kg= e 0. 85 m= f 1.30 m= g 0. 95 m= Solution: MM 1 M 2 + M 3 + M 4 += x c 1 M M 2 aM 3 ab+()+ ... calculation. Given: r 50 mm= t 15 mm= a 150 mm= b 15 mm= c 150 mm= Solution: y c bc b 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ at b a 2 + ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + π r 2 ba+ r+()+ bc at+ π r 2 + = y...

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Engineering Mechanics Statics - Examples Part 1 pdf

Engineering Mechanics Statics - Examples Part 1 pdf

... 10 6 N= μg110 6− × gm= kN 10 3 N= Given: x 453 20 kN= y 56 8 10 5 × () mm= z 0.0 056 3 mg= Solution: a() x 45. 3MN= b() y 56 .8km= c() z 5. 63μg= Problem 1-7 Evaluate ( ab⋅ )/c to three significant figures ... writing from the publisher. Engineering Mechanics - Statics Chapter 1 Problem 1-1 6 Two particles have masses m 1 and m 2 , respectively. If they are a distance d a...

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Engineering Mechanics Statics - Examples Part 2 pps

Engineering Mechanics Statics - Examples Part 2 pps

... from the publisher. Engineering Mechanics - Statics Chapter 2 Given: F 40 20 50 − ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ N= L 25 m= Solution: r L F F = r 14.9 7 .5 18.6− ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ m= Problem 2-9 7 Express each of ... from the publisher. Engineering Mechanics - Statics Chapter 2 Problem 2-1 27 Determine the angle θ between the edges of the sheet-metal bracket. Given: a 50 mm= b...

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Engineering Mechanics Statics - Examples Part 4 potx

Engineering Mechanics Statics - Examples Part 4 potx

... publisher. Engineering Mechanics - Statics Chapter 4 Units Used: kN 10 3 N= Given: a 16 mm= F 2.30 kN= θ 60− 80 ()= Solution: M A θ () Fa( ) cos θ deg () = 50 0 50 100 0 50 N.m M A θ () θ Problem 4-1 7 The ... in⋅= Problem 4 -5 5 The force F acts on the gear in the direction shown. Determine the moment of this force about the y axis. Given: F 50 lb= a 3in= θ 1 60 deg=...

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Engineering Mechanics Statics - Examples Part 6 doc

Engineering Mechanics Statics - Examples Part 6 doc

... permission in writing from the publisher. Engineering Mechanics - Statics Chapter 5 Given: a 50 mm= b 50 mm= c 10 mm= k 5 N m = Solution: Initial Guesses: F 0 .5 N= y A 1mm= y B 1mm= Given cy A − ab+ y B y A − a = ... form or by any means, without permission in writing from the publisher. Engineering Mechanics - Statics Chapter 5 Problem 5- 4 5 The mobile crane...

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Engineering Mechanics Statics - Examples Part 8 pptx

Engineering Mechanics Statics - Examples Part 8 pptx

... Engineering Mechanics - Statics Chapter 6 pppj socket joint at C. Given: M 50 kg= g 9.81 m s 2 = a 0. 25 m= b 0 .5 m= c 2m= Solution: hb 2 a 2 −= AB a− c− h ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ = ... F GH , () = E y F CD F CF F CG F FG F GH ⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ 9. 75 11. 25 3.207 6.8− 9. 155 9. 155 ⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ kN= Positive (T) Negative (C) Problem 6-4...

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