Advanced Engineering Dynamics 2010 Part 11 pps
... shall only be con- cerned with the overall dynamics and not with the detail. This is a vast subject area of which dynamics is a substantial and vital part. 8.2 Typical arrangements 8.2.1 CARTESIAN ... SUCCESSIVE ROTATIONS ABOUT FIXED AXES 8 Robot Arm Dynamics 8.1 Introduction In this chapter we examine the way in which three-dimensional dynamics is applied to a sys-...
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Advanced Engineering Dynamics 2010 Part 14 ppsx
... reverse then a body at rest disintegrates into two particles having kinetic energy at the expense of the rest mass of the system. In conventional engineering situations this does not occur, but ... input at the joint in the direction of the vertical part of the 'T'. As a result an axial wave is generated in the vertical part and symmetri- cal bending waves are generated...
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Advanced Engineering Dynamics 2010 Part 2 doc
... a group of particles 15 1.13 Newton's laws for a group of particles Consider a group of n particles, three of which are shown in Fig. 1.1 1, where the ith parti- cle has ... on the particle is the vector sum of the forces due to each other particle in the group and the resultant of the external forces. If & is the force on particle i due to particle ......
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Advanced Engineering Dynamics 2010 Part 3 ppt
... then the time integral will be integrated by Parts because 6u = 0 at t, and t2. The second term in equation (3.18) is Integrating by parts gives (3.19) 50 Hamilton S principle ... integrating by parts, h 6x 1; - It:mi 6x dt - kx 6x dt = 0 4 (3.10) Rotating fiame of reference and velocity-dependent potentials 37 It is interesting to note that for a charged par...
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Advanced Engineering Dynamics 2010 Part 6 docx
... ba t = A = -(0 - esinca) 2 2 Using equations (5.37) and (5.38) Fig. 5.1 1 110 Dynamics of vehicles Fig. 5.18 Y = m(; + rU - pw) Z = m(w + pV - qu) The moment ... conditions when o = oo. Thus 1 12 Dynamics of vehicles (5.96) 1 2 where C, is the drag coeficient. The drag coefficient is the sum of two parts, the first being the sum...
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Advanced Engineering Dynamics 2010 Part 8 docx
... - - a. = e-' [ J e' (1 - 0) dI + constant] - = e-' [e' - 11 = (1 - e-') (the constant = 1 as Go = 0 when i = 0) - - - - a, = e-' ... f"= gA-1 (6.29) At x = 0 there must be continuity of velocity. For the short bar the particle velocity is super- imposed on the pre-impact speed of J! Thus (6.30) V +...
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Advanced Engineering Dynamics 2010 Part 9 potx
... (6.109) Integrating the first term once more by parts and noting that the end forces are workless leads to and finally since 0 = avBx (6 .110 ) Because 6v is arbitrary (except at t, and ... Therefore 1 0, - v.u - - 2 VJI KC, - Equation (6.12 1) is written as and differentiating partially with respect to x gives (6.126) (6.127) or This is known as the Emosh...
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