An introduction to multiagent systems - part 1 potx
An introduction to multiagent systems - part 1 potx
... mechanism is that it is a dominant- strategy solution to the quasi-linear problem: Theorem 7.2.3 Given a quasi-linear mechanism design problem M, the VCG mechanism for M is a direct dominant-strategy ... Result: The Vickrey-Clarke-Groves Mechanism If we are to design a truthful mechanism that is not dictatorial, we are going to have to relax some of the conditions of the Gibbard-Satte...
Ngày tải lên: 08/08/2014, 11:21
An introduction to multiagent systems - part 2 potx
... otherwise. E(u 1 ) = 2s 1 0 u 1 dv 2 + 10 2s 1 u 1 dv 2 = 2s 1 0 (v 1 − s 1 )dv 2 + 10 2s 1 0dv 2 = 2s 1 0 (v 1 − s 1 )dv 2 = (v 1 − s 1 )v 1 | 2s 1 0 = 2v 1 s 1 − 2s 2 1 Now we have a closed ... player 1 wins when player 2’s valuation is less than twice his own bid, s 1 , and he loses otherwise. Then player 1 s utility is simply (v 1...
Ngày tải lên: 08/08/2014, 11:21
An introduction to multiagent systems - part 3 docx
... 2 m/2 +1 to express in the OR-of-XOR language. It is also possible to define a language of XOR-of-OR bids, and even a lan- guage allowing arbitrary nesting of OR and XOR statements here (we refer to the ... discussed. The XOR, OR-of-XORs, XOR-of-OR, OR/XOR, and OR* languages are all powerful enough to express all valuations. Second, the efficiencies of the OR-of- XOR and XOR-of-OR langu...
Ngày tải lên: 08/08/2014, 11:21
An Introduction to Database Systems 8Ed - C J Date - Solutions Manual Episode 1 Part 5 pptx
... ┌────┐ │ │ a1 │ b1 │ c1 │ │ a1 │ │ B │ │ │ C │ │ │ a1 │ b1 │ c2 │ │ │ ├════┤ │ ├════┤ │ │ a1 │ b2 │ c1 │ │ │ │ b1 │ │ │ c1 │ │ │ a1 │ b2 │ c2 │ │ │ │ b2 │ │ │ c2 │ │ │ a2 │ b1 │ c1 │ │ │ └────┘ ... supplier S1 supplies the set of parts {P1,P2,P3,P4,P5,P6}. It is thus a "true fact" that supplier S1 supplies the set of parts {P1,P2,P3,P4,P5} and the set of parts {P1,P2,P3,P4}...
Ngày tải lên: 06/08/2014, 01:21
An Introduction to Database Systems 8Ed - C J Date - Solutions Manual Episode 1 Part 6 pot
... TIMES T9 ) AS T10, /* T10 {SA,SB,P#} : SA supplies some part, SB supplies some part, and part P# is supplied by some supplier */ ( T10 MINUS T7 ) AS T 11, /* T 11 {SA,SB,P#} : part P# is supplied, ... not by both SA and SB */ ( T6 INTERSECT T 11 ) AS T12, /* T12 {SA,SB,P#} : part P# is supplied by SA but not by SB */ ( T5 INTERSECT T 11 ) AS T13, /* T13 {SA,SB,P#} :...
Ngày tải lên: 06/08/2014, 01:21