Fundamentals of Structural Analysis Episode 1 Part 6 doc
Fundamentals of Structural Analysis Episode 1 Part 2 pot
... equation: ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ 66656463 62 61 56555453 52 51 46454443 42 41 36353433 32 31 26 2 524 2 322 21 1 615 1 413 1 21 1 KKKKKK KKKKKK KKKKKK KKKKKK KKKKKK KKKKKK ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 v u v u v u = ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 y x y x y x P P P P P P (15 ) where ... representation: ⎪ ⎪...
Ngày tải lên: 05/08/2014, 09:20
Fundamentals of Structural Analysis Episode 1 Part 3 pps
... trusses shown. (1- a) (1- b) (1- c) (2-a)(2-b)(2-c) (3- a) (3- b) (3- c) (4-a)(4-b)(4-c) Problem 1. 3m 4m 3 kN 3m 4m 3m 8 kN 3m 4m 3m 8 kN 3 kN 3m 4m 4 kN 3m 4m 4 kN 3m 2m 6 kN 2m 1. 5m 1. 2 m 1. 6 m 0.9 m 2 m2 m 1. 2 ... joint. 4 F 6 F 3 F 2 3 5 4 3 4 5 1 F 3 F 1 R y1 R x1 3 4 5 F 4 F 2 R y5 5 R x5 3 5 4 10 kN 3@ 2m=6m 1 3 2 4 5 6 7 1 2 3 5 6 7 8 10 11...
Ngày tải lên: 05/08/2014, 09:20
Fundamentals of Structural Analysis Episode 1 Part 4 pps
... shown. (1- a) (1- b) (2) (3) (4- a) (4- b) Problem 2. 4m 4@ 3m =12 m 1 kN a b 4m 4@ 3m =12 m 1 kN a b 12 kN 4 @ 4m =16 m 2m 3m a b c 6@3m =18 m 4m 4m 12 kN a b c 3@3m=9m 4m 4m 15 kN a AB b c 3@3m=9m 4m 4m 15 kN a AB b ... form: x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1...
Ngày tải lên: 05/08/2014, 09:20
Fundamentals of Structural Analysis Episode 1 Part 5 pdf
... -0. 71 -1. 00 -3.40 -4.80 6 -56 .56 17 ,680 -3.20 1. 00 0.94 -3.20 -3.00 7 40.00 25, 000 1. 60 -0. 71 0.33 -1. 14 0 .53 8 -56 .56 17 ,680 -3.20 0.00 -0.47 0.00 1. 50 9 -40.00 25, 000 -1. 60 -0. 71 -0.33 1. 14 ... (mm/kN) 1 -0.33 25, 000 -0. 013 -0.8 0. 010 -0.032 0.026 2 0 33,333 0 -0.6 0 -0. 018 0. 011 3 0 25, 000 0 -0.8 0 -0.032 0.026 4 0 .50 33,333 0. 0 15 -0.6 -0.009 -0...
Ngày tải lên: 05/08/2014, 09:20
Fundamentals of Structural Analysis Episode 1 Part 6 doc
... kN/m 2m 6m 6 kN 2m 6 kN 3 kN/m 2m 3m 3m 6 kN 2m 6 kN 15 kN 15 kN 3 kN/m 2m 3m 3m 6 kN 2m 6 kN 15 kN 15 kN 6 kN -6 kN 9 kN -9 kN V V Beam and Frame Analysis: Force Method, Part I by S. T. Mau 11 1 Shear ... 3m 3m 6 kN 2m 6 kN V V 5 kN 5 kN 6 kN 1 kN 6 kN 2m 3m 3m 2m 30 kN-m M 6 kN/m 6 kN/m M 1 kN/m 1 kN/m 15 kN-m 12 kN-m -12 kN-m -15 kN-m Beam an...
Ngày tải lên: 05/08/2014, 09:20
Fundamentals of Structural Analysis Episode 2 Part 6 doc
... 17 .63 0 42. 98 σ due to axial force (kN/cm 2 ) 0.0 72 0.0 72 0.088 0.088 0. 125 0. 124 σ due to moment (kN/cm 2 ) 0 0.0 06 0 0.013 0 0.0 32 Total σ (kN/cm 2 ) 0.0 72 0.078 0.088 0.101 0. 125 0.1 56 Error ... depth of the beam, h, is the same for both members. The fixed-end moments are obtained from the above table: P L /2 L /2 w L L /2 L /2 L 0.2L0.2L 0.6L h h b a 0....
Ngày tải lên: 05/08/2014, 09:20