Fundamentals of Structural Analysis Episode 1 Part 2 pot

Fundamentals of Structural Analysis Episode 1 Part 2 pot

... equation: ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ 66656463 62 61 56555453 52 51 46454443 42 41 36353433 32 31 26 2 524 2 322 21 1 615 1 413 1 21 1 KKKKKK KKKKKK KKKKKK KKKKKK KKKKKK KKKKKK ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 v u v u v u = ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 y x y x y x P P P P P P (15 ) where ... representation: ⎪ ⎪...

Ngày tải lên: 05/08/2014, 09:20

Fundamentals of Structural Analysis Episode 1 Part 3 pps

... m 5kN 1. 2 m 1m 1m 1 kN 2 m2 m 1m 1m 2 kN 2 m2 m 1m 1m 2 kN 1 kN Truss Analysis: Force Method, Part I by S. T. Mau 49 This particular cut separates the truss into two parts. We shall use the left part ... joint. 4 F 6 F 3 F 2 3 5 4 3 4 5 1 F 3 F 1 R y1 R x1 3 4 5 F 4 F 2 R y5 5 R x5 3 5 4 10 kN 3@2m=6m 1 3 2 4 5 6 7 1 2 3 5 6 7 8 10 11 2m 9 4 Truss Ana...

Ngày tải lên: 05/08/2014, 09:20

Fundamentals of Structural Analysis Episode 1 Part 4 pps

... form: x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 1 kN 1 kN 1 kN 1 kN 1 kN 1 kN Truss Analysis: ... EntryReaction Number Force Number 2i -1 Coeff. 2i Coeff. 1 4 1 -1. 0 2 0.0 2 5 1 0.0 2 -1. 0 3 6 5 0.0 6 -1. 0 Cont...

Ngày tải lên: 05/08/2014, 09:20