Engineering Tribology Episode 2 Part 2 pdf
Engineering Tribology Episode 1 Part 3 pdf
... max. ISO VG 2 1.98 2. 2 2. 42 ISO VG 3 2. 88 3 .2 3. 52 ISO VG 5 4.14 4.6 5.06 ISO VG 7 6. 12 6.8 7.48 ISO VG 10 9.00 10 11.0 ISO VG 15 13.5 15 16.5 ISO VG 22 19.8 22 24 .2 ISO VG 32 28.8 32 35 .2 ISO VG ... 41.4 46 50.6 ISO VG 68 61 .2 68 74.8 ISO VG 100 90.0 100 110 ISO VG 150 135 150 165 ISO VG 22 0 198 22 0 24 2 ISO VG 320 28 8 320 3 52 ISO VG 460 414 460 506 ISO VG...
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 4 doc
... stability [°C] 135 21 0 23 0 24 0 25 0 23 0 28 0 430 430 370 370 Kinematic viscosity [cSt] at -20 °C 170 193 16 85 115 20 0 850 1000 0°C 75 75 16 38 47 100 25 0 25 00 8000 440 40°C ... 180 185 20 0 26 0 24 0 29 0 none none Pour point [°C] -57 -60 - 62 -57 -65 -70 -70 -7 +4 -30 -67 Oxidative stability [°C] 24 0 29 0 2...
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 5 doc
... sulfonate 0 0.05 0.10 0.15 0 .20 0 .25 0.30 0.35 0 40 80 120 160 20 0 24 0 20 60 100 140 180 22 0 Coefficient of friction Tem p erature [°C] FIGURE 3 .24 Effect of dispersants on ... Interface, Lubrication Engineering, Vol. 55, 1999, pp. 22 -27 . 67 P.M.E. Cann, Thin-Film Grease Lubrication, Proc. Inst. Mech. Eng., Part J, Journal of Engineering Tribolog...
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Engineering Tribology Episode 1 Part 6 pptx
... yields: ∂p 2 ∂x z 2 h 2 ( ( z 3 + (U 1 − U 2 ) z 2 2h + U 2 z q x = 3 − 0 h which after simplifying gives the flow rate in the ‘x’ direction, q x = − h 3 12 ∂p ∂x + (U 1 + U 2 ) h 2 (4.18) Similarly ... + ∂p ∂x z 2 2 (U − U) 12 ηz h − ∂p ∂x hz 2 + ηU = ηu 2 Dividing and simplifying gives the expression for velocity in the ‘x’ direction: u = ∂p ∂x − zh 2 (...
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 7 pptx
... h 0 2 [] 6Uη 2B π sec ¯ θ 3 1 2 (θ+ sinθcosθ) − (sinθcos 2 θ + 2sinθ) + C= L W 2B π dθ ⌠ ⌡ θ 1 θ 2 Integrating yields: h 0 2 6UηB 2 sec ¯ θ 3 θ 2 4 = L W 4 π 2 θ 1 θ 2 + sin 2 θ 4 + () cos 3 θ 3 + 2cosθ+Cθ (4.95) TEAM ... 0.6 0.4 42 0.8 0.431 1.0 0. 422 1 .2 0.414 1.4 0.406 1.6 0.399 1.8 0.393 2 .0 0.387 2 .2 0.381 2 .4 0.376 2 ....
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 8 pptx
... −ε 2 ) 2 2ε ⌠ ⌡ 0 π dθ = (1 +εcosθ) 3 sin 2 θ 2( 1 −ε 2 ) 3 /2 π 4 L 2 () − y 2 ⌠ ⌡ − L 2 L dy = 6 L 3 2 Substituting yields: W 1 = − c 2 (1 −ε 2 ) 2 UηL 3 ε 2 (4.105) W 2 = 4c 2 (1 ... = ⌠ ⌡ 0 π dθdy Rc 2 (1 + εcosθ) 3 3UηεRsinθcosθ 4 L 2 () − y 2 ⌠ ⌡ − L 2 L 2 ⌠ ⌡ 0 π dθ c 2 3Uηε 4 L 2 () − y 2 ⌠ ⌡ − L 2 L 2 (1 + εcosθ) 3 sinθco...
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 9 pps
... 2. 5 12 0.563 0. 528 -1.090 -0.383 - - - 1.385 - 2 H [W] 3.9307× 10 3 -0.706 1.577 0.477 2. 240 1 .28 7 0 .24 9 -0 .20 4 - 1 . 324 - - 3 ε 1 .26 66× 10 -2 0.536 1. 120 -1.050 -0.578 -0 .21 7 0.476 0 .21 4 - - - 4 ... [kg/s] 1.4791× 10 3 0. 524 -1.070 0 .21 2 1.381 0. 821 1.457 0 .27 6 - - 5 T max [°F] 3.8608 0.137 -0.063 0. 024 0.387 0 .27 2 -0.311 0.081 - - - 6 T max −T s [°F] 2....
Ngày tải lên: 05/08/2014, 09:19
Engineering Tribology Episode 1 Part 10 potx
... Journal of Tribology, Vol. 111, 1989, Part 1, pp. 22 0 -22 7, Part 2, pp. 22 8 -23 7. 58 Y. Mitsuya, Stokes Roughness Effects on Hydrodynamic Lubrication, Part 2 - Effects under Slip Flow Boundary Conditions, ... + G ∂ 2 M v ∂x* 2 + ( ( R L 2 ∂ 2 M v ∂y* 2 (5.4) where parameters ‘F’ and ‘G’ for journal bearings are as follows: ∂h* ∂x* + ( ( R L 2 [( ( 2 ∂h* ∂y* ( (...
Ngày tải lên: 05/08/2014, 09:19