Ferroelectrics Material Aspects Part 2 pdf
... routes: Na 2 CO 3 + Bi 2 O 3 + 4TiO 2 → 4Na 0.5 Bi 0.5 TiO 3 + CO 2 (1) Bi 4 Ti 3 O 12 + 5TiO 2 + 2Na 2 CO 3 → 8Na 0.5 Bi 0.5 TiO 3 + 2CO 2 (2) In route (1), the starting materials ... V DB(|S (2, 1)|) 10V DB(|S (2, 1)|) 15V DB(|S (2, 1)|) 20 V DB(|S (2, 1)|) 25 V DB(|S (2, 1)|) 30V DB(|S (2, 1)|) 35V 0.5 1 1.5 2 2.5 3 3.5 4 4.5 Frequency (GHz) -40 -35 -30...
Ngày tải lên: 19/06/2014, 13:20
Ferroelectrics Material Aspects Part 5 pptx
... ln(J) V 1 /2 ln(J/E) 0.00.51.01. 52. 02. 5 -26 .5 -26 .0 -25 .5 -25 .0 -24 .5 Pool-Frenkel current Without treatment Nitrogen treatment 10 min ln(J/E) V 1 /2 a) b) Ferroelectrics – Material Aspects ... et al., 20 03, Zhu et al., 20 02a, Zhu et al., 20 02b, Zhu et al., 20 02c) and 30 0–3 20 for graded films prepared by sol-gel methods (Jain et al., 20 03,...
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Ferroelectrics Material Aspects Part 13 pptx
... -20 0 -100 0 100 20 0 -60 -40 -20 0 20 40 60 -20 0 -100 0 100 20 0 -20 0 20 -20 0 -100 0 100 20 0 -40 -20 0 20 40 -20 0 -100 0 100 20 0 -40 -20 0 20 40 -20 0 -100 0 100 20 0 -10 0 10 -20 0 -100 0 100 20 0 -20 -10 0 10 20 -20 0 ... 0 1 /2 1 /2 U (Å 2 ) 1.31(6) 2. 27(5) 3.14(5) 3.60(4) O (2) x -0. 029 2(14) 0 0 .27 82( 3) y 0.0303(14) 0 .22 59(8)...
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Ferroelectrics Material Aspects Part 14 pptx
... T = T c1 – T c2 , f = F 32 21 6 8 , q 2 = 21 2 2 2 , p 2 = - 2 21 3 2 P 2 , e = 120 3 /2 2 () E, 2 = 32 021 6 8s , and s = 2 02 2Q s is the ... Ferroelectrics – Material Aspects 4 62 120 160 20 0 24 0 28 0 40 80 120 160 20 0 24 0 100 kHz 10 kHz 1 kHz 120 Hz C, pF T, K a) 120 160 20 0...
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Ferroelectrics Applications Part 2 pptx
... mm). 0 20 00 4000 6000 8000 24 25 26 27 28 29 30 31 Ti (mol%) ε r After poling Before poling 1 2 3 4 (a) 0 20 40 60 80 100 24 25 26 27 28 29 30 31 Ti (mol%) k 31 (%) 0 28 0 560 840 1 120 1400 fc 31 ... (pC/N) k 32 (%) Pr (μC/cm 2 ) Ec (V/mm) Aging (100) PZNT 86 21 00 55 24 00 42 35 600 Good (100) PMNT 65 1030 60 24 20 22 300 NG (110) PZNT 30~60 300...
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Ferroelectrics Material Aspects Part 1 potx
... et al., 20 00, 20 02; Ramirez et al, 20 00; Home et al., 20 01; Adams, et al., 20 02; Sinclair et al., 20 02; Maurya, et al. 20 08; Prakash, et al., 20 08; Zhu, et al., 20 08; Kim, et al., 20 10). CCT ... Figure 28 shows the tuning of the fabricated filter. The best Fig. 27 . Photograph of a ring filter 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 Frequency (GH...
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Ferroelectrics Material Aspects Part 3 doc
... interface. Ferroelectrics – Material Aspects 68 Fig. 23 . Evolution of the current density as a function of a positive DC electrical field for a BTS film. O 0 → V 0 2+ + 2e - + 1/2O 2 (18) ... Substrates 83 -800 -600 -400 -20 0 0 20 0 400 600 800 -60 -40 -20 0 20 40 60 Polarization(uC/cm 2 ) Electric Field(kV/cm) -600 -400 -20 0 0 20 0 400 600 0 2...
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Ferroelectrics Material Aspects Part 4 potx
... 1 020 3040506070 0 20 40 60 80 100 M 33 cer. =1.58 10 -14 m 2 /V 2 M 33 =2. 39 10 -14 m 2 /V 2 M 33 =2. 08 10 -14 m 2 /V 2 M 33 =2. 59 10 -14 m 2 /V 2 2 Hz s.c. Fit of data at 2 Hz 20 Hz s.c. Fit ... dielectric constant for CoFe 2 O 4 composite thick film from 25 to 20 0 o C. Ferroelectrics – Material Aspects 124 closing to 1 and even abo...
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Ferroelectrics Material Aspects Part 6 ppt
... Ba 0.6 Sr 0.4 TiO 3 Films for Property –Specific Device Applications. Integrated Ferroelectrics Vol. 100, 36-47. Ferroelectrics – Material Aspects 186 or 42 33 2 11 22 42 X O Ti Mn O Ti Mn O ... (d) x=0.05. Scan size: 2* 2 µm By adding Mn 2+ ions (and some oxygen from e.g. the atmosphere) we may find 24 2 1 2 X OO OMn V Mn O ...
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Ferroelectrics Material Aspects Part 7 ppt
... 24 wt% and 12 wt%, respectively. Ferroelectrics – Material Aspects 22 0 10 20 30 40 50 60 70 80 (e) (d) (c) (b) (a) 22 2 22 0 20 0 111 113 013 134 122 322 23 3 022 0 62 004 043 133 1 12 222 0 12 150 0 42 0 02 211 122 140 111 1 12 131 130 110 0 02 120 101 021 001 020 ... (Avdeev 20 02; Lee 20 00). As shown in Fig. 21 ., La(Mg 0.5 Ti 0.5 )O 3 fo...
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