Wind Turbines Part 3 pptx

... used where the two airflows mix. Wind Turbines 94 Using equation (1). Power = ½ * ρ * TSA * V 3 Power = ½ * 1.2 93 * 3. 09252 * 6 3 Power = 431 .9 W 3. 2 Calculation for Condition 2 A ... (1). Power = ½ * ρ * TSA * V 3 Power = ½ * 1.205 * 3. 09252 * 16 3 Power = 7 631 .8 W. While condition 1 gave an output of 431 .9 W, condition 2 gave an output of 7 631 .8 W. Th...

Ngày tải lên: 20/06/2014, 05:20

... 1.2 1 .3 enercon’s E -33 0 .33 0 33 .4 37 44 50 4 5 6 2.1 2.2 2 .3 enercon’s E-48 0.800 48.0 50 60 76 7 8 3. 1 3. 2 enercon’s E- 53 0.800 52.9 60 73 9 10 11 4.1 4.2 4 .3 Vestas ... 78 138 20 21 9.1 9.2 enercon’s E-70 2 .30 0 71.0 58 1 13 22 23 24 10.1 10.2 10 .3 Vestas V90 3. 000 90.0 95 105 125 Table 1. Commercial wind turbine...

Ngày tải lên: 20/06/2014, 05:20

... for wind farm micrositing than the SM one. Meshing Methods Fitness (×10 −4 ) Output (kW) WT Numbers SM-45 ◦ 8.4240 1 31 958 39 ETM-0 ◦ 8.0465 34 164 40 ETM-10 ◦ 8.2490 31 957 38 ETM-40 ◦ 8.2 133 32 779 ... the wind turbines determine the orientation Meshing Methods Fitness (×10 3 ) Output (kW) WT Numbers ETM-10 ◦ 1 .37 27 21 737 44 ETM-20 ◦ 1 .38 42 21556 44 ETM-40 ◦ 1 .38 32...

Ngày tải lên: 20/06/2014, 05:20

... Students 2.9 Connected Sentence Cards 3. Instructions 3. 1 Activity Template (Blank) 3. 2 Sample Lesson Plan 3. 3 Sound Connections Demo 3. 6 Going Further 3. 15 Connected Speech Templates ... Exchanges 6. Instructions 6.1 Activity Template (Blank) 6 .3 Multi-Purpose Texts 7. Instructions 7.1 Reading Race – Lesson Plan 7 .3 Discussion Questions 8. Instruc...

Ngày tải lên: 13/12/2013, 21:15

Ngày tải lên: 13/12/2013, 21:15

Ngày tải lên: 14/12/2013, 10:15

... 09_ScrollingDataBinding using System; using System.Windows.Forms; using System.Data; using System.Data.SqlClient; public class ScrollingDataBinding : System.Windows.Forms.Form { private Button retrieveButton; ... ScrollingDataBinding() { this.AutoScaleBaseSize = new System.Drawing.Size(5, 13) ; this.ClientSize = new System.Drawing.Size(464, 2 53) ; this.Text = "09_Scro...

Ngày tải lên: 15/12/2013, 02:16

... contrast, ψ n+1 j =(1+iH∆t) −1 ψ n j (19.2 .34 ) These are both first-order accurate in time, as can be seen by expanding equation (19.2 .32 ). However, neither operator in (19.2 .33 ) or (19.2 .34 ) is unitary. 19 .3 Initial Value ... the form i ∂ψ ∂t = Hψ (19.2 .30 ) where the operator H is H = − ∂ 2 ∂x 2 + V (x)(19.2 .31 ) The formal solution of equation (19.2 .30 ) is ψ(x, t)=e −iHt ψ(x,...

Ngày tải lên: 15/12/2013, 04:15